वर्गमूल सर्पिल में \(\sqrt{75}\) का सरल रूप कौन सा है?

In a square root spiral, what is the simplified form of \(\sqrt{75}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(5\sqrt{3}\)

Step 1

Concept

\(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\). Take the perfect square (25) outside.

Step 2

Why this answer is correct

The correct answer is B. \(5\sqrt{3}\). \(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\). Take the perfect square (25) outside.

Step 3

Exam Tip

\(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\)। पूर्ण वर्ग (25) को बाहर निकालें।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \(\sqrt{75}\) का सरल रूप कौन सा है? / In a square root spiral, what is the simplified form of \(\sqrt{75}\)?

Correct Answer: B. \(5\sqrt{3}\). Explanation: \(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\)। पूर्ण वर्ग (25) को बाहर निकालें। / \(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\). Take the perfect square (25) outside.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\). Take the perfect square (25) outside.

What exam hint can help solve this Mathematics question?

\(\sqrt{75}=\sqrt{25\times3}=5\sqrt{3}\)। पूर्ण वर्ग (25) को बाहर निकालें।