\(\sqrt{1295}\) के बाद बनने वाला कर्ण वर्गमूल सर्पिल में किस सटीक मान पर होगा?

In a square root spiral, the hypotenuse formed after \(\sqrt{1295}\) will be at which exact value?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{1296}=36\)

Step 1

Concept

The next hypotenuse is \(\sqrt{1296}\). Since \(1296=36^2\), its value is (36).

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{1296}=36\). The next hypotenuse is \(\sqrt{1296}\). Since \(1296=36^2\), its value is (36).

Step 3

Exam Tip

अगला कर्ण \(\sqrt{1296}\) होगा। \(1296=36^2\), इसलिए इसका मान (36) है।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{1295}\) के बाद बनने वाला कर्ण वर्गमूल सर्पिल में किस सटीक मान पर होगा? / In a square root spiral, the hypotenuse formed after \(\sqrt{1295}\) will be at which exact value?

Correct Answer: A. \(\sqrt{1296}=36\). Explanation: अगला कर्ण \(\sqrt{1296}\) होगा। \(1296=36^2\), इसलिए इसका मान (36) है। / The next hypotenuse is \(\sqrt{1296}\). Since \(1296=36^2\), its value is (36).

Which concept should I revise for this Mathematics MCQ?

The next hypotenuse is \(\sqrt{1296}\). Since \(1296=36^2\), its value is (36).

What exam hint can help solve this Mathematics question?

अगला कर्ण \(\sqrt{1296}\) होगा। \(1296=36^2\), इसलिए इसका मान (36) है।