\(\sqrt{1295}\) के बाद बनने वाला कर्ण वर्गमूल सर्पिल में किस सटीक मान पर होगा?
In a square root spiral, the hypotenuse formed after \(\sqrt{1295}\) will be at which exact value?
Explanation opens after your attempt
A. \(\sqrt{1296}=36\)
Concept
The next hypotenuse is \(\sqrt{1296}\). Since \(1296=36^2\), its value is (36).
Why this answer is correct
The correct answer is A. \(\sqrt{1296}=36\). The next hypotenuse is \(\sqrt{1296}\). Since \(1296=36^2\), its value is (36).
Exam Tip
अगला कर्ण \(\sqrt{1296}\) होगा। \(1296=36^2\), इसलिए इसका मान (36) है।
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