यदि (x=3), तो \(\frac{x^2+2x-3}{x}\) का मान क्या होगा?

If (x=3), what is the value of \(\frac{x^2+2x-3}{x}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

The numerator is (32+2(3)-3=12). Then \(\frac{12}{3}=4\).

Step 2

Why this answer is correct

The correct answer is A. (4). The numerator is (32+2(3)-3=12). Then \(\frac{12}{3}=4\).

Step 3

Exam Tip

अंश (32+2(3)-3=12) है। फिर \(\frac{12}{3}=4\) मिलेगा।

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Mathematics Answer, Explanation and Revision Hints

यदि (x=3), तो \(\frac{x^2+2x-3}{x}\) का मान क्या होगा? / If (x=3), what is the value of \(\frac{x^2+2x-3}{x}\)?

Correct Answer: A. (4). Explanation: अंश (32+2(3)-3=12) है। फिर \(\frac{12}{3}=4\) मिलेगा। / The numerator is (32+2(3)-3=12). Then \(\frac{12}{3}=4\).

Which concept should I revise for this Mathematics MCQ?

The numerator is (32+2(3)-3=12). Then \(\frac{12}{3}=4\).

What exam hint can help solve this Mathematics question?

अंश (32+2(3)-3=12) है। फिर \(\frac{12}{3}=4\) मिलेगा।