यदि (q(x)=(k+1)2x-9+\(k^2-1\)x-5-4x+6) और (k=-1), तो (q(x)) की डिग्री क्या है?
If (q(x)=(k+1)2x-9+\(k^2-1\)x-5-4x+6) and (k=-1), what is the degree of (q(x))?
Explanation opens after your attempt
C. (1)
Concept
Putting (k=-1) removes both \(x^9\) and \(x^5\) terms. The remaining (-4x+6) has degree (1).
Why this answer is correct
The correct answer is C. (1). Putting (k=-1) removes both \(x^9\) and \(x^5\) terms. The remaining (-4x+6) has degree (1).
Exam Tip
(k=-1) रखने पर \(x^9\) और \(x^5\) दोनों पद हट जाते हैं। बचा (-4x+6) है जिसकी डिग्री (1) है।
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