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If a proof writes \(\sqrt{2}=\frac{m}{n}\) but does not state lowest form, what is the biggest weakness?

Answer and explanation

Correct answer: The contradiction will not be clear when both become even

Assuming \(\sqrt{2}=\frac{m}{n}\) gives \(m^2=2n^2\). This shows that \(m\) is even, and then \(n\) is also even. However, this becomes a contradiction only if \(\frac{m}{n}\) was stated to be in lowest terms, meaning that \(m\) and \(n\) are coprime. Both being even contradicts coprimality; being even alone is not a contradiction. Exam tip: In such irrationality proofs, always state that the fraction is in lowest terms or that the numerator and denominator are coprime.

Related tags

Number SystemsIrrationality ProofSquare Root 2Proof By ContradictionCoprime NumbersProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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