यदि \(a_n=48\left(\frac{1}{2}\right)^{n-1}\) है, तो \(a_3+a_5\) का मान क्या है?

If \(a_n=48\left(\frac{1}{2}\right)^{n-1}\), what is the value of \(a_3+a_5\)?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

B. (15)

Step 1

Concept

\(a_3=12\) and \(a_5=3\), so the sum is (15). Use powers carefully with a fractional ratio.

Step 2

Why this answer is correct

The correct answer is B. (15). \(a_3=12\) and \(a_5=3\), so the sum is (15). Use powers carefully with a fractional ratio.

Step 3

Exam Tip

\(a_3=12\) और \(a_5=3\), इसलिए योग (15) है। भिन्न अनुपात में घात सावधानी से लगाएं।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_n=48\left(\frac{1}{2}\right)^{n-1}\) है, तो \(a_3+a_5\) का मान क्या है? / If \(a_n=48\left(\frac{1}{2}\right)^{n-1}\), what is the value of \(a_3+a_5\)?

Correct Answer: B. (15). Explanation: \(a_3=12\) और \(a_5=3\), इसलिए योग (15) है। भिन्न अनुपात में घात सावधानी से लगाएं। / \(a_3=12\) and \(a_5=3\), so the sum is (15). Use powers carefully with a fractional ratio.

Which concept should I revise for this Mathematics MCQ?

\(a_3=12\) and \(a_5=3\), so the sum is (15). Use powers carefully with a fractional ratio.

What exam hint can help solve this Mathematics question?

\(a_3=12\) और \(a_5=3\), इसलिए योग (15) है। भिन्न अनुपात में घात सावधानी से लगाएं।