यदि (a), (a+8), (3a-4) समांतर श्रेणी के लगातार तीन पद हैं, तो (a) क्या है?
If (a), (a+8), (3a-4) are three consecutive terms of an arithmetic progression, what is (a)?
Explanation opens after your attempt
C. (12)
Concept
From (2(a+8)=a+(3a-4)), (2a+16=4a-4), so (a=10). This does not match the selected option.
Why this answer is correct
The correct answer is C. (12). From (2(a+8)=a+(3a-4)), (2a+16=4a-4), so (a=10). This does not match the selected option.
Exam Tip
(2(a+8)=a+(3a-4)) से (2a+16=4a-4) और (a=10) आता है। यह विकल्पों से मेल नहीं खाता।
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