यदि \(a_1=1\) और \(a_{n+1}=a_n+n^2+n\) है तो \(a_4\) क्या होगा?

If \(a_1=1\) and \(a_{n+1}=a_n+n^2+n\), what is \(a_4\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (23)

Step 1

Concept

The terms are (1,3,9,21), so \(a_4=21\). The values of \(n^2+n\) are (2,6,12).

Step 2

Why this answer is correct

The correct answer is C. (23). The terms are (1,3,9,21), so \(a_4=21\). The values of \(n^2+n\) are (2,6,12).

Step 3

Exam Tip

पद (1,3,9,21) नहीं बल्कि \(a_4=21\) है। \(n^2+n\) के मान (2,6,12) हैं।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=1\) और \(a_{n+1}=a_n+n^2+n\) है तो \(a_4\) क्या होगा? / If \(a_1=1\) and \(a_{n+1}=a_n+n^2+n\), what is \(a_4\)?

Correct Answer: C. (23). Explanation: पद (1,3,9,21) नहीं बल्कि \(a_4=21\) है। \(n^2+n\) के मान (2,6,12) हैं। / The terms are (1,3,9,21), so \(a_4=21\). The values of \(n^2+n\) are (2,6,12).

Which concept should I revise for this Mathematics MCQ?

The terms are (1,3,9,21), so \(a_4=21\). The values of \(n^2+n\) are (2,6,12).

What exam hint can help solve this Mathematics question?

पद (1,3,9,21) नहीं बल्कि \(a_4=21\) है। \(n^2+n\) के मान (2,6,12) हैं।