यदि \(a_1=1\) और \(a_{n+1}=a_n+n^2+3n\) है तो \(a_5\) क्या होगा?

If \(a_1=1\) and \(a_{n+1}=a_n+n^2+3n\), what is \(a_5\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. (61)

Step 1

Concept

The added values are (4,10,18,28), so \(a_5=61\). Exam tip: first find the values of \(n^2+3n\).

Step 2

Why this answer is correct

The correct answer is A. (61). The added values are (4,10,18,28), so \(a_5=61\). Exam tip: first find the values of \(n^2+3n\).

Step 3

Exam Tip

जुड़ने वाले मान (4,10,18,28) हैं इसलिए \(a_5=61\) है। पहले \(n^2+3n\) के मान अलग निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=1\) और \(a_{n+1}=a_n+n^2+3n\) है तो \(a_5\) क्या होगा? / If \(a_1=1\) and \(a_{n+1}=a_n+n^2+3n\), what is \(a_5\)?

Correct Answer: A. (61). Explanation: जुड़ने वाले मान (4,10,18,28) हैं इसलिए \(a_5=61\) है। पहले \(n^2+3n\) के मान अलग निकालें। / The added values are (4,10,18,28), so \(a_5=61\). Exam tip: first find the values of \(n^2+3n\).

Which concept should I revise for this Mathematics MCQ?

The added values are (4,10,18,28), so \(a_5=61\). Exam tip: first find the values of \(n^2+3n\).

What exam hint can help solve this Mathematics question?

जुड़ने वाले मान (4,10,18,28) हैं इसलिए \(a_5=61\) है। पहले \(n^2+3n\) के मान अलग निकालें।