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A calculator displays \(\sqrt{3}\) as 1.7320508. Which conclusion is correct based on this display?

Answer and explanation

Correct answer: यह केवल सन्निकट मान है; \(\sqrt{3}\) का दशमलव प्रसार असांत और अनावर्ती है।

A calculator shows only a rounded approximation. Since \(1^2<3<2^2\), \(\sqrt{3}\) lies between 1 and 2, but its decimal expansion is non-terminating and non-repeating, so it is irrational. Exam tip: never treat a finite display as the exact decimal expansion.

Related tags

Number SystemsIrrational NumbersSquare Root 3Decimal ExpansionMisconception AnalysisProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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