Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 421-430 of 600 questions.
In the line \(y=\frac{4}{3}x-6\), how much should (x) increase to increase (y) by (24)?
B. (18)
परिवर्तन \(\frac{4}{3}\Delta x=24\) होगा। इससे \(\Delta x=18\) मिलता है। / The change is \(\frac{4}{3}\Delta x=24\). This gives \(\Delta x=18\).
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If (p=6) and (q=-8) in (y=px+q), which statement is correct?
B. रेखा बढ़ती है और (y)-अवरोध ऋणात्मक हैThe line increases and the (y)-intercept is negative
(p=6) धनात्मक ढाल देता है और (q=-8) ऋणात्मक (y)-अवरोध देता है। इसलिए रेखा बढ़ती है। / (p=6) gives a positive slope and (q=-8) gives a negative (y)-intercept. So the line increases.
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If (5x+ay=40) has (y)-intercept (8), what is (a)?
C. (5)
(x=0) रखने पर (ay=40) और \(y=\frac{40}{a}\) मिलता है। \(\frac{40}{a}=8\) से (a=5) है। / Putting (x=0) gives (ay=40) and \(y=\frac{40}{a}\). From \(\frac{40}{a}=8\), (a=5).
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If (bx+8y=48) has slope (-3), what is (b)?
C. (24)
(8y=-bx+48) से ढाल \(-\frac{b}{8}\) है। \(-\frac{b}{8}=-3\) से (b=24) है। / From (8y=-bx+48), the slope is \(-\frac{b}{8}\). From \(-\frac{b}{8}=-3\), (b=24).
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The line (y=(n-4)x+(2n-3)) has (y)-intercept (11). What is its slope?
B. (3)
(2n-3=11) से (n=7) मिलता है। ढाल (n-4=3) है। / From (2n-3=11), (n=7). The slope is (n-4=3).
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The line (y=(t-8)x+(t+5)) has slope (6). What is its (y)-intercept?
D. (19)
(t-8=6) से (t=14) मिलता है। (y)-अवरोध (t+5=19) है। / From (t-8=6), (t=14). The (y)-intercept is (t+5=19).
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Which line cuts the (y)-axis at ( (0,-10) ) and increases (y) by (28) when (x) increases by (4)?
A. (y=7x-10)
ढाल \(\frac{28}{4}=7\) है और (y)-अवरोध (-10) है। इसलिए रेखा (y=7x-10) है। / The slope is \(\frac{28}{4}=7\) and the (y)-intercept is (-10). So the line is (y=7x-10).
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Which line cuts the (y)-axis at ( (0,14) ) and decreases (y) by (30) when (x) increases by (5)?
B. (y=-6x+14)
ढाल \(-\frac{30}{5}=-6\) है और (y)-अवरोध (14) है। इसलिए (y=-6x+14) सही है। / The slope is \(-\frac{30}{5}=-6\) and the (y)-intercept is (14). So (y=-6x+14) is correct.
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If (y=(a+4)x+(a-10)) passes through the origin, what will be its slope?
C. (14)
मूल बिंदु से गुजरने के लिए (a-10=0) होगा। इसलिए (a=10) और ढाल (a+4=14) है। / To pass through the origin, (a-10=0). Thus (a=10) and the slope is (a+4=14).
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If (y=(2u+1)x+(u-2)) has (y)-intercept (6), what is the slope?
C. (17)
(u-2=6) से (u=8) मिलता है। ढाल (2u+1=17) है। / From (u-2=6), (u=8). The slope is (2u+1=17).
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