Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
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If (p(x)=x+5r) and (q(x)=x-8r), what type of polynomial is (p(x)-q(x))?
B. नियतांक बहुपदConstant polynomial
(p(x)-q(x)=13r) है। (x) के संदर्भ में यह नियतांक बहुपद है। / (p(x)-q(x)=13r). With respect to (x), it is a constant polynomial.
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If (p(x)=10x-29), what is the correct value of (p(p(3)))?
B. (-19)
(p(3)=1) और (p(1)=10-29=-19) है। अंदर वाले मान को पहले निकालें। / (p(3)=1) and (p(1)=10-29=-19). Find the inner value first.
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If (p(x)=6x+5), what is the value of (p(p(0)))?
C. (35)
(p(0)=5) और (p(5)=35) है। रचना में अंदर वाला मान पहले निकालें। / (p(0)=5) and (p(5)=35). In composition, find the inner value first.
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For which value will the zero of ((n+6)x+4n-3) be (1)?
A. \(n=-\frac{3}{5}\)
शून्यक (1) होने पर (n+6+4n-3=0) होगा। इससे (5n+3=0) और \(n=-\frac{3}{5}\) मिलता है। / If the zero is (1), then (n+6+4n-3=0). Thus (5n+3=0) and \(n=-\frac{3}{5}\).
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If (p(x)=\frac{x}{8}+a) and (p(24)=17), what is the value of (a)?
C. (14)
(p(24)=3+a=17) से (a=14) मिलता है। भिन्न रूप में पहले (x) का मान रखें। / From (p(24)=3+a=17), we get (a=14). In fractional form, substitute the value of (x) first.
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If (p(x)=7x+a) and (q(x)=4x-12), what is (a) if the zero of (p(x)+q(x)) is (2)?
A. (-10)
(p(x)+q(x)=11x+a-12) है। (x=2) रखने पर (22+a-12=0) से (a=-10) मिलता है। / (p(x)+q(x)=11x+a-12). Substituting (x=2) gives (22+a-12=0), so (a=-10).
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For which value will the zero of (p(x)=(c-7)x+8c) be (-4)?
A. (c=-7)
(-4(c-7)+8c=0) से (4c+28=0) मिलता है। इसलिए (c=-7) है। / From (-4(c-7)+8c=0), we get (4c+28=0). Therefore (c=-7).
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If the zero of (p(x)=(c-3)x+6c) is (-6), which conclusion is correct?
C. कोई (c) नहींNo (c)
(-6(c-3)+6c=0) से (18=0) जैसा असंभव परिणाम मिलता है। इसलिए कोई (c) नहीं है। / From (-6(c-3)+6c=0), we get the impossible result (18=0). Therefore no (c) exists.
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If (p(x)=rx-12) and (p(6)=30), what is the value of (p(-2))?
B. (-26)
(6r-12=30) से (r=7) मिलता है। इसलिए (p(-2)=7(-2)-12=-26) है। / From (6r-12=30), we get (r=7). Therefore (p(-2)=7(-2)-12=-26).
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If (p(x)=ax+15) and (p(2)=p(8)-30), what is (a)?
B. (5)
(2a+15=(8a+15)-30) से (2a=8a-30) मिलता है। इसलिए (a=5) है। / From (2a+15=(8a+15)-30), we get (2a=8a-30). Therefore (a=5).
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