यदि (p(x)=7x+a) और (q(x)=4x-12), तो (p(x)+q(x)) का शून्यक (2) होने पर (a) क्या है?
If (p(x)=7x+a) and (q(x)=4x-12), what is (a) if the zero of (p(x)+q(x)) is (2)?
Explanation opens after your attempt
A. (-10)
Concept
(p(x)+q(x)=11x+a-12). Substituting (x=2) gives (22+a-12=0), so (a=-10).
Why this answer is correct
The correct answer is A. (-10). (p(x)+q(x)=11x+a-12). Substituting (x=2) gives (22+a-12=0), so (a=-10).
Exam Tip
(p(x)+q(x)=11x+a-12) है। (x=2) रखने पर (22+a-12=0) से (a=-10) मिलता है।
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