Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 561-570 of 600 questions.
If (p(x)=9x-17), what is (p(x+3))?
A. (9x+10)
(p(x+3)=9(x+3)-17=9x+10) है। (x) की जगह पूरा (x+3) रखें। / (p(x+3)=9(x+3)-17=9x+10). Substitute the whole (x+3) in place of (x).
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If (p(x)=19-7x), which is (p(2x))?
B. (19-14x)
(p(2x)=19-7(2x)=19-14x) है। प्रतिस्थापन करते समय पूरे (2x) को रखें। / (p(2x)=19-7(2x)=19-14x). While substituting, use the whole (2x).
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For which value will (\(t^2-8t+15\)x+(t-3)) not remain a linear polynomial?
A. (t=3) या (t=5)(t=3) or (t=5)
रेखीय होने के लिए \(t^2-8t+15\neq0\) चाहिए। \(t^2-8t+15=0\) से (t=3) या (t=5) मिलता है। / For it to be linear, \(t^2-8t+15\neq0\) is needed. From \(t^2-8t+15=0\), (t=3) or (t=5).
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If (p(x)=kx-14) and (p(7)=p(-1)), when will (p(x)) remain linear?
C. कभी नहींNever
(p(7)=p(-1)) से (7k-14=-k-14) और (k=0) मिलता है। (k=0) पर बहुपद रेखीय नहीं रहता। / From (p(7)=p(-1)), (7k-14=-k-14), so (k=0). At (k=0), the polynomial is not linear.
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If (p(x)=7x+2) and (q(x)=15x-6), what is the degree of (q(x)-2p(x))?
B. (1)
(q(x)-2p(x)=15x-6-2(7x+2)=x-10) है। इसकी डिग्री (1) है। / (q(x)-2p(x)=15x-6-2(7x+2)=x-10). Its degree is (1).
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Which option has zero \(\frac{29}{11}\) for a linear polynomial?
A. (11x-29)
(11x-29=0) से \(x=\frac{29}{11}\) मिलता है। शून्यक के लिए बहुपद को (0) के बराबर रखें। / From (11x-29=0), we get \(x=\frac{29}{11}\). Set the polynomial equal to (0) to find the zero.
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If (p(x)=12x-25), what is (p(x+1)-p(x))?
B. (12)
(p(x+1)=12x-13) और (p(x)=12x-25) है। अंतर (12) मिलता है। / (p(x+1)=12x-13) and (p(x)=12x-25). The difference is (12).
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C. \(\lambda>3\)
शून्यक \(-\frac{21}{\lambda}\) है। \(-\frac{21}{\lambda}>-7\) और \(\lambda>0\) से \(\lambda>3\) मिलता है। / The zero is \(-\frac{21}{\lambda}\). From \(-\frac{21}{\lambda}>-7\) and \(\lambda>0\), we get \(\lambda>3\).
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In which option will (p(x)=ax+b) have zero (-11)?
A. (b=11a) और \(a\neq0\)(b=11a) and \(a\neq0\)
शून्यक (-11) होने पर (-11a+b=0) होगा। इसलिए (b=11a) और \(a\neq0\) चाहिए। / If the zero is (-11), then (-11a+b=0). So (b=11a) and \(a\neq0\) are needed.
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If (p(x)=x+5r) and (q(x)=x-8r), what is (p(x)+q(x))?
A. (2x-3r)
जोड़ने पर (x+5r+x-8r=2x-3r) मिलता है। पैरामीटर वाले पदों को भी मिलाएं। / On adding, (x+5r+x-8r=2x-3r). Combine the parameter terms too.
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