If (a*b=a+b), what is the identity element?
Step 1: For identity element (e), (a*e=a) and (e*a=a). Step 2: (a+0=a) and (0+a=a). Step 3: For addition-like operations, check (0) first.
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SubjectsMathematics
द्विआधारी संक्रियाएँ
In Class 12 Mathematics, this topic introduces binary operations as functions that combine two elements of a set to produce another element of the same set. Within the chapter Relations and Functions, students learn to identify whether an operation is well-defined and closed, represent it through tables or algebraic rules, and examine key properties such as commutativity, associativity, identity elements, and inverses. Examples involving familiar number systems help connect these ideas with broader function concepts.
TOPIC PRACTICE
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Step 1: For identity element (e), (a*e=a) and (e*a=a). Step 2: (a+0=a) and (0+a=a). Step 3: For addition-like operations, check (0) first.
View question detailsStep 1: An identity element (e) must satisfy (ae=a) and (ea=a). Step 2: (a\cdot 1=a) and (1\cdot a=a). Step 3: For multiplication-like operations, (1) is the first candidate.
View question detailsStep 1: We need (a*e=a). Step 2: From (a+e+1=a), we get (e=-1). Step 3: To find identity, cancel (a) from both sides and solve for (e).
View question detailsStep 1: For (a*e=a), we need (a+e-1=a). Step 2: This gives (e=1), and (e*a=e+a-1=a) also works. Step 3: It is a good habit to check identity from both sides.
View question detailsStep 1: (a*0=a+0+a\cdot 0=a). Step 2: (0*a=0+a+0\cdot a=a), so (0) works from both sides. Step 3: The identity element leaves every element unchanged.
View question detailsStep 1: For inverse (x), we need (5*x=0). Step 2: (5+x=0) gives (x=-5). Step 3: In addition, the inverse is the element with the opposite sign.
View question detailsStep 1: For inverse (x), we need (4x=1). Step 2: Hence (x=\frac{1}{4}). Step 3: In multiplication, think of the reciprocal as the inverse.
View question detailsStep 1: For inverse (x), (3*x=1) must hold. Step 2: (3+x-1=1) gives (x=-1). Step 3: First identify the identity, then form the inverse equation.
View question detailsStep 1: For inverse (x), (2*x=-1) must hold. Step 2: (2+x+1=-1) gives (x=-4). Step 3: In inverse questions, set the result equal to the identity element.
View question detailsStep 1: First calculate inside the bracket: (2*3=2+3=5). Step 2: Then (5*4=5+4=9). Step 3: In bracket questions, do the inner operation first.
View question detailsStep 1: First (3*4=3+4=7). Step 2: Now (2*7=2+7=9). Step 3: The operation rule remains the same, only the order follows the brackets.
View question detailsStep 1: ((2*3)*4=9) and (2*(3*4)=9). Step 2: The two values are equal, showing associativity in this example. Step 3: In addition-based operations, changing brackets does not change the value.
View question detailsStep 1: First (5*2=5-2=3). Step 2: Then (3*1=3-1=2). Step 3: In subtraction, bracket order can change the answer.
View question detailsThe governing concept is a defined binary operation together with evaluation of a nested expression. The rule a * b = a − b must be used whenever the symbol * appears; it does not mean ordinary multiplication. Because the expression contains parentheses, evaluate the inner operation first: 2 * 1 = 2 − 1 = 1. Substitute this result into the outer operation: 5 * (2 * 1) = 5 * 1 = 5 − 1 = 4. Therefore option B is correct. Option A is the result of stopping after the inner operation. Option C may arise from adding or mishandling the operands, and option D does not follow the defined rule. Correct bracket order and the given operation rule are both essential.
View question detailsStep 1: ((5*2)*1=2). Step 2: (5*(2*1)=4), so the two values are not equal. Step 3: One unequal example is enough to disprove associativity.
View question detailsStep 1: First (2*3=2\cdot 3=6). Step 2: Then (6*4=6\cdot 4=24). Step 3: Under multiplication, multiply the two numbers each time.
View question detailsStep 1: First (3*4=3\cdot 4=12). Step 2: Then (2*12=2\cdot 12=24). Step 3: In multiplication, changing brackets still gives the same final product.
View question detailsStep 1: (\max(a,b)) means choosing the greater value. Step 2: Between (3) and (7), the greater value is (7). Step 3: In a maximum-based rule, do not add or multiply the numbers.
View question detailsStep 1: (\min(a,b)) means choosing the smaller value. Step 2: Between (8) and (5), the smaller value is (5). Step 3: In a minimum-based operation, simply choose the smaller element.
View question detailsStep 1: (a*b=\max(a,b)) and (b*a=\max(b,a)). Step 2: The greater value is the same in both cases, so the results are equal. Step 3: Maximum and minimum operations are easy to test for commutativity.
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