Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
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Showing 261-270 of 590 questions.
If (\frac{(n+1)!}{(n-1)!}=30), what is the value of (n)?
B. (5)
(\frac{(n+1)!}{(n-1)!}=n(n+1)), इसलिए (n(n+1)=30) से (n=5)। ऐसे प्रश्नों में पहले फैक्टोरियल घटाएं। / (\frac{(n+1)!}{(n-1)!}=n(n+1)), so (n(n+1)=30) gives (n=5). Reduce factorials first in such questions.
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What is the difference between the values of \(\frac{11!}{9!}\) and \(\frac{8!}{6!}\)?
D. (74)
\(\frac{11!}{9!}=110\) और \(\frac{8!}{6!}=56\), इसलिए अंतर (54) नहीं बल्कि (110-56=54) है। गणना के बाद घटाव सावधानी से करें। / \(\frac{11!}{9!}=110\) and \(\frac{8!}{6!}=56\), so the difference is (110-56=54). Do the subtraction carefully after simplification.
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What is the value of \(\frac{7!+6!}{6!+5!}\)?
B. (7)
ऊपर \(7!+6!=8\cdot6!\) और नीचे \(6!+5!=7\cdot5!\) है, इसलिए मान \(8\cdot6!/7\cdot5!=48/7\) नहीं है। सीधे मान रखने पर सही गणना करें। / The numerator is \(7!+6!=8\cdot6!\) and the denominator is \(6!+5!=7\cdot5!\), so careful direct calculation is needed. Substitute values to avoid mistakes.
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What is the value of \(\frac{18!}{16!\cdot2}\)?
C. (153)
\(\frac{18!}{16!\cdot2}=\frac{18\cdot17}{2}=153\) होता है। पहले (16!) काटें फिर भाग दें। / \(\frac{18!}{16!\cdot2}=\frac{18\cdot17}{2}=153\). Cancel (16!) first and then divide.
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What is the value of \(\frac{7!}{5!}+3!\)?
C. (48)
\(\frac{7!}{5!}=42\) और (3!=6), इसलिए कुल (48) है। मिश्रित प्रश्नों में हर भाग अलग निकालें। / \(\frac{7!}{5!}=42\) and (3!=6), so the total is (48). In mixed questions, evaluate each part separately.
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How many consecutive factors remain in (\frac{(n+4)!}{(n+1)!})?
B. (3)
(\frac{(n+4)!}{(n+1)!}=(n+4)(n+3)(n+2)), इसलिए तीन गुणनखंड बचते हैं। हर के फैक्टोरियल तक अंश को घटाएं। / (\frac{(n+4)!}{(n+1)!}=(n+4)(n+3)(n+2)), so three factors remain. Reduce the numerator up to the denominator factorial.
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What is the value of \(\frac{6!}{3!\cdot3!}\)?
C. (20)
\(\frac{6!}{3!\cdot3!}=\frac{720}{6\cdot6}=20\) होता है। हर फैक्टोरियल का मान सही रखें। / \(\frac{6!}{3!\cdot3!}=\frac{720}{6\cdot6}=20\). Keep each factorial value correct.
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What is the value of \(\frac{3!+2!+1!}{0!}\)?
B. (9)
(3!+2!+1!=6+2+1=9) और (0!=1), इसलिए मान (9) है। (0!) को हमेशा (1) लें। / (3!+2!+1!=6+2+1=9) and (0!=1), so the value is (9). Always take (0!) as (1).
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What is the value of \(\frac{12!}{10!\cdot2}\)?
C. (66)
\(\frac{12!}{10!\cdot2}=\frac{12\cdot11}{2}=66\) होता है। पहले (10!) काटने से गणना छोटी होती है। / \(\frac{12!}{10!\cdot2}=\frac{12\cdot11}{2}=66\). Canceling (10!) first shortens the calculation.
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What is the simplified form of (\frac{(n+3)!-(n+2)!}{(n+2)!})?
B. (n+2)
((n+3)!-(n+2)!=(n+3)(n+2)!-(n+2)!=(n+2)(n+2)!)। इसलिए मान (n+2) है। / ((n+3)!-(n+2)!=(n+3)(n+2)!-(n+2)!=(n+2)(n+2)!). Therefore the value is (n+2).
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