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While proving (\sqrt{5}) irrational, both (a) and (b) turn out divisible by (5). What is its effect on (\gcd(a,b))?

Answer and explanation

Correct answer: (\gcd(a,b)) will be at least (5)

Step 1: Both numbers are divisible by (5). Step 2: Therefore their greatest common divisor cannot remain (1); it will be at least (5). Step 3: This breaks the coprimality condition.

Related tags

Real-NumbersRoot5GcdCoprimeProof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real NumbersMathematics

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