कौन सा विकल्प \(x=\sqrt{2}+\sqrt{3}\) के लिए सही द्विघात समीकरण है?

Which option is a correct quadratic equation for \(x=\sqrt{2}+\sqrt{3}\)?

Explanation opens after your attempt
Correct Answer

A. \(x^2-10x^0+1=0\)

Step 1

Concept

Actually \(x=\sqrt{2}+\sqrt{3}\) satisfies \(x^4-10x^2+1=0\), not a simple quadratic here. Read powers carefully in such trick questions.

Step 2

Why this answer is correct

The correct answer is A. \(x^2-10x^0+1=0\). Actually \(x=\sqrt{2}+\sqrt{3}\) satisfies \(x^4-10x^2+1=0\), not a simple quadratic here. Read powers carefully in such trick questions.

Step 3

Exam Tip

\(x^2=5+2\sqrt{6}\) और संयुग्मी के साथ गुणन से \(x^4-10x^2+1=0\) मिलता है। दिए विकल्प में \(x^0=1\) इसलिए पहला रूप सही नहीं दिखता, ध्यान से पढ़ें।

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Mathematics Answer, Explanation and Revision Hints

कौन सा विकल्प \(x=\sqrt{2}+\sqrt{3}\) के लिए सही द्विघात समीकरण है? / Which option is a correct quadratic equation for \(x=\sqrt{2}+\sqrt{3}\)?

Correct Answer: A. \(x^2-10x^0+1=0\). Explanation: \(x^2=5+2\sqrt{6}\) और संयुग्मी के साथ गुणन से \(x^4-10x^2+1=0\) मिलता है। दिए विकल्प में \(x^0=1\) इसलिए पहला रूप सही नहीं दिखता, ध्यान से पढ़ें। / Actually \(x=\sqrt{2}+\sqrt{3}\) satisfies \(x^4-10x^2+1=0\), not a simple quadratic here. Read powers carefully in such trick questions.

Which concept should I revise for this Mathematics MCQ?

Actually \(x=\sqrt{2}+\sqrt{3}\) satisfies \(x^4-10x^2+1=0\), not a simple quadratic here. Read powers carefully in such trick questions.

What exam hint can help solve this Mathematics question?

\(x^2=5+2\sqrt{6}\) और संयुग्मी के साथ गुणन से \(x^4-10x^2+1=0\) मिलता है। दिए विकल्प में \(x^0=1\) इसलिए पहला रूप सही नहीं दिखता, ध्यान से पढ़ें।