Which option explains why (\sqrt{a^2}=a) is not always true?

If (a<0), then (\sqrt{a^2}=|a|)

The principal square root is non-negative so (\sqrt{a^2}=|a|). In exams be careful when (a) is negative.

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.

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Correct answer: If (a<0), then (\sqrt{a^2}=|a|)

The principal square root is non-negative so (\sqrt{a^2}=|a|). In exams be careful when (a) is negative.

What is the correct answer to this question?

If (a<0), then (\sqrt{a^2}=|a|)

Why is this the correct answer?

The principal square root is non-negative so (\sqrt{a^2}=|a|). In exams be careful when (a) is negative.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.

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