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Which option correctly describes the nature of the expression (\sqrt{45}+\sqrt{80}-\sqrt{125})?

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Answer and explanation

Correct answer: Irrational number

Simplify first: \(\sqrt{45}=3\sqrt{5}\), \(\sqrt{80}=4\sqrt{5}\), \(\sqrt{125}=5\sqrt{5}\). So the expression equals \(3\sqrt{5}+4\sqrt{5}-5\sqrt{5}=2\sqrt{5}\). Since \(\sqrt{5}\) is irrational, multiplying by the nonzero rational 2 yields an irrational number, so \(2\sqrt{5}\) is irrational. Why others are wrong: it cannot be rational because \(\sqrt{5}\) is irrational; it is not an integer; it is not zero because the coefficient 2 is nonzero. Exam tip: factor and combine like surd terms (same \(\sqrt{\;\;}\)) to simplify quickly.

Related tags

SurdsIrrational-NumbersReal-NumbersNumber-ClassificationSimplification

Frequently asked questions

What is the correct answer to this question?

Irrational number

Why is this the correct answer?

Simplify first: \(\sqrt{45}=3\sqrt{5}\), \(\sqrt{80}=4\sqrt{5}\), \(\sqrt{125}=5\sqrt{5}\). So the expression equals \(3\sqrt{5}+4\sqrt{5}-5\sqrt{5}=2\sqrt{5}\). Since \(\sqrt{5}\) is irrational, multiplying by the nonzero rational 2 yields an irrational number, so \(2\sqrt{5}\) is irrational. Why others are wrong: it cannot be rational because \(\sqrt{5}\) is irrational; it is not an integer; it is not zero because the coefficient 2 is nonzero. Exam tip: factor and combine like surd terms (same \(\sqrt{\;\;}\)) to simplify quickly.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.

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