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Which option correctly describes the nature of \(\frac{1}{2}+\sqrt{2}\)?

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Answer and explanation

Correct answer: Irrational number

\(\frac{1}{2}\) is rational and \(\sqrt{2}\) is irrational. If their sum were rational, then \(\sqrt{2}=(\frac{1}{2}+\sqrt{2})-\frac{1}{2}\) would be a difference of rationals and thus rational, contradicting that \(\sqrt{2}\) is irrational. Hence \(\frac{1}{2}+\sqrt{2}\) is irrational. The closest distractor "rational" is incorrect for the reason above; "integer" and "terminating decimal" are specific types of rationals so they are also incorrect. Exam tip: memorize that rational + irrational = irrational (contradiction proof is quick and useful in exams).

Related tags

Rational-IrrationalReal-NumbersClassificationProperties-Of-Numbers

Frequently asked questions

What is the correct answer to this question?

Irrational number

Why is this the correct answer?

\(\frac{1}{2}\) is rational and \(\sqrt{2}\) is irrational. If their sum were rational, then \(\sqrt{2}=(\frac{1}{2}+\sqrt{2})-\frac{1}{2}\) would be a difference of rationals and thus rational, contradicting that \(\sqrt{2}\) is irrational. Hence \(\frac{1}{2}+\sqrt{2}\) is irrational. The closest distractor "rational" is incorrect for the reason above; "integer" and "terminating decimal" are specific types of rationals so they are also incorrect. Exam tip: memorize that rational + irrational = irrational (contradiction proof is quick and useful in exams).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.

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