समीकरण (px+6y=18) और (5x+3y=11) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है?

Which condition is correct for (px+6y=18) and (5x+3y=11) to have a unique solution?

Explanation opens after your attempt
Correct Answer

B. \(p \ne 10\)

Step 1

Concept

For a unique solution \(p/5 \ne 6/3\) must hold. Therefore \(p \ne 10\) is the correct condition.

Step 2

Why this answer is correct

The correct answer is B. \(p \ne 10\). For a unique solution \(p/5 \ne 6/3\) must hold. Therefore \(p \ne 10\) is the correct condition.

Step 3

Exam Tip

अद्वितीय हल के लिए \(p/5 \ne 6/3\) होना चाहिए। इसलिए \(p \ne 10\) सही शर्त है।

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समीकरण (px+6y=18) और (5x+3y=11) का अद्वितीय हल होने के लिए कौन-सी शर्त सही है? / Which condition is correct for (px+6y=18) and (5x+3y=11) to have a unique solution?

Correct Answer: B. \(p \ne 10\). Explanation: अद्वितीय हल के लिए \(p/5 \ne 6/3\) होना चाहिए। इसलिए \(p \ne 10\) सही शर्त है। / For a unique solution \(p/5 \ne 6/3\) must hold. Therefore \(p \ne 10\) is the correct condition.

Which concept should I revise for this Mathematics MCQ?

For a unique solution \(p/5 \ne 6/3\) must hold. Therefore \(p \ne 10\) is the correct condition.

What exam hint can help solve this Mathematics question?

अद्वितीय हल के लिए \(p/5 \ne 6/3\) होना चाहिए। इसलिए \(p \ne 10\) सही शर्त है।