\(7x^2+8x+1=0\) के मूल क्या होंगे?
What will be the roots of \(7x^2+8x+1=0\)?
Explanation opens after your attempt
Correct Answer
A. \(x=-\frac{1}{7},-1\)
Concept
((7x+1)(x+1)=0), so \(x=-\frac{1}{7}\) and (-1). In exams, ((7x+1)=0) gives \(-\frac{1}{7}\).
Why this answer is correct
The correct answer is A. \(x=-\frac{1}{7},-1\). ((7x+1)(x+1)=0), so \(x=-\frac{1}{7}\) and (-1). In exams, ((7x+1)=0) gives \(-\frac{1}{7}\).
Exam Tip
((7x+1)(x+1)=0), इसलिए \(x=-\frac{1}{7}\) और (-1) हैं। परीक्षा में ((7x+1)=0) से \(-\frac{1}{7}\) मिलता है।
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