(\left\(\sqrt{11}+2\right\)2) का मान क्या है?

What is the value of (\left\(\sqrt{11}+2\right\)2)?

Explanation opens after your attempt
Correct Answer

A. \(15+4\sqrt{11}\)

Step 1

Concept

Use ((a+b)2=a-2+2ab+b-2).

Step 2

Why this answer is correct

(\(\sqrt{11}\)2+2\sqrt{11}\times2+22=11+4\sqrt{11}+4=15+4\sqrt{11}).

Step 3

Exam Tip

Forgetting the middle term (2ab) is a common mistake. चरण 1: ((a+b)2=a-2+2ab+b-2) लगाएं। चरण 2: (\(\sqrt{11}\)2+2\sqrt{11}\times2+22=11+4\sqrt{11}+4=15+4\sqrt{11})। चरण 3: मध्य पद (2ab) को भूलना सामान्य गलती है।

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Mathematics Answer, Explanation and Revision Hints

(\left\(\sqrt{11}+2\right\)2) का मान क्या है? / What is the value of (\left\(\sqrt{11}+2\right\)2)?

Correct Answer: A. \(15+4\sqrt{11}\). Explanation: चरण 1: ((a+b)2=a-2+2ab+b-2) लगाएं। चरण 2: (\(\sqrt{11}\)2+2\sqrt{11}\times2+22=11+4\sqrt{11}+4=15+4\sqrt{11})। चरण 3: मध्य पद (2ab) को भूलना सामान्य गलती है। / Step 1: Use ((a+b)2=a-2+2ab+b-2). Step 2: (\(\sqrt{11}\)2+2\sqrt{11}\times2+22=11+4\sqrt{11}+4=15+4\sqrt{11}). Step 3: Forgetting the middle term (2ab) is a common mistake.

Which concept should I revise for this Mathematics MCQ?

Use ((a+b)2=a-2+2ab+b-2).

What exam hint can help solve this Mathematics question?

Forgetting the middle term (2ab) is a common mistake. चरण 1: ((a+b)2=a-2+2ab+b-2) लगाएं। चरण 2: (\(\sqrt{11}\)2+2\sqrt{11}\times2+22=11+4\sqrt{11}+4=15+4\sqrt{11})। चरण 3: मध्य पद (2ab) को भूलना सामान्य गलती है।