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What is the value of \(\left(\dfrac{2}{3}\right)^{-2}\times \dfrac{4}{9}\)?\(\left(\dfrac{2}{3}\right)^{-2}\times \dfrac{4}{9}\) का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (,1,)(,1,)
\(\left(\dfrac{2}{3}\right)^{-2}=\left(\dfrac{3}{2}\right)^2=\dfrac{9}{4}\), so the product is (1). In exams, a fraction is inverted under a negative exponent.\(\left(\dfrac{2}{3}\right)^{-2}=\left(\dfrac{3}{2}\right)^2=\dfrac{9}{4}\), इसलिए गुणनफल (1) है। परीक्षा में ऋणात्मक घात में भिन्न उलट जाती है।
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