(\left\(\dfrac{2}{3}\right\)^{-2}\times \dfrac{4}{9}) का मान क्या है?
What is the value of (\left\(\dfrac{2}{3}\right\)^{-2}\times \dfrac{4}{9})?
Explanation opens after your attempt
Correct Answer
A. (,1,)
Concept
(\left\(\dfrac{2}{3}\right\)^{-2}=\left\(\dfrac{3}{2}\right\)2=\dfrac{9}{4}), so the product is (1). In exams, a fraction is inverted under a negative exponent.
Why this answer is correct
The correct answer is A. (,1,). (\left\(\dfrac{2}{3}\right\)^{-2}=\left\(\dfrac{3}{2}\right\)2=\dfrac{9}{4}), so the product is (1). In exams, a fraction is inverted under a negative exponent.
Exam Tip
(\left\(\dfrac{2}{3}\right\)^{-2}=\left\(\dfrac{3}{2}\right\)2=\dfrac{9}{4}), इसलिए गुणनफल (1) है। परीक्षा में ऋणात्मक घात में भिन्न उलट जाती है।
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