समीकरण \(x^2+16x+64=0\) के मूल कौन से हैं?
What are the roots of \(x^2+16x+64=0\)?
Explanation opens after your attempt
B. (-8) और (-8)(-8) and (-8)
Concept
(x-2+16x+64=(x+8)2). Therefore both roots are (-8).
Why this answer is correct
The correct answer is B. (-8) और (-8) / (-8) and (-8). (x-2+16x+64=(x+8)2). Therefore both roots are (-8).
Exam Tip
(x-2+16x+64=(x+8)2) है। इसलिए दोनों मूल (-8) हैं।
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