\(5x^2+9x-2=0\) के मूल क्या हैं?

What are the roots of \(5x^2+9x-2=0\)?

Explanation opens after your attempt
Correct Answer

A. \(x=\frac{1}{5},-2\)

Step 1

Concept

(5x-2+9x-2=(5x-1)(x+2)), so the roots are \(\frac{1}{5}\) and (-2). In exams, correct standard form is very important.

Step 2

Why this answer is correct

The correct answer is A. \(x=\frac{1}{5},-2\). (5x-2+9x-2=(5x-1)(x+2)), so the roots are \(\frac{1}{5}\) and (-2). In exams, correct standard form is very important.

Step 3

Exam Tip

(5x-2+9x-2=(5x-1)(x+2)), इसलिए मूल \(\frac{1}{5}\) और (-2) हैं। परीक्षा में सही मानक रूप बहुत जरूरी है।

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Mathematics Answer, Explanation and Revision Hints

\(5x^2+9x-2=0\) के मूल क्या हैं? / What are the roots of \(5x^2+9x-2=0\)?

Correct Answer: A. \(x=\frac{1}{5},-2\). Explanation: (5x-2+9x-2=(5x-1)(x+2)), इसलिए मूल \(\frac{1}{5}\) और (-2) हैं। परीक्षा में सही मानक रूप बहुत जरूरी है। / (5x-2+9x-2=(5x-1)(x+2)), so the roots are \(\frac{1}{5}\) and (-2). In exams, correct standard form is very important.

Which concept should I revise for this Mathematics MCQ?

(5x-2+9x-2=(5x-1)(x+2)), so the roots are \(\frac{1}{5}\) and (-2). In exams, correct standard form is very important.

What exam hint can help solve this Mathematics question?

(5x-2+9x-2=(5x-1)(x+2)), इसलिए मूल \(\frac{1}{5}\) और (-2) हैं। परीक्षा में सही मानक रूप बहुत जरूरी है।