यदि \(x^2+tx+12=0\) के वास्तविक मूल नहीं हैं तो (t) के लिए सही शर्त क्या है?

If \(x^2+tx+12=0\) has no real roots, what is the correct condition for (t)?

Explanation opens after your attempt
Correct Answer

A. \(t^2<48\)

Step 1

Concept

For no real roots, (D<0) is required. So \(t^2-48<0\), that is \(t^2<48\).

Step 2

Why this answer is correct

The correct answer is A. \(t^2<48\). For no real roots, (D<0) is required. So \(t^2-48<0\), that is \(t^2<48\).

Step 3

Exam Tip

वास्तविक मूल नहीं होने के लिए (D<0) होना चाहिए। इसलिए \(t^2-48<0\), अर्थात \(t^2<48\)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x^2+tx+12=0\) के वास्तविक मूल नहीं हैं तो (t) के लिए सही शर्त क्या है? / If \(x^2+tx+12=0\) has no real roots, what is the correct condition for (t)?

Correct Answer: A. \(t^2<48\). Explanation: वास्तविक मूल नहीं होने के लिए (D<0) होना चाहिए। इसलिए \(t^2-48<0\), अर्थात \(t^2<48\)। / For no real roots, (D<0) is required. So \(t^2-48<0\), that is \(t^2<48\).

Which concept should I revise for this Mathematics MCQ?

For no real roots, (D<0) is required. So \(t^2-48<0\), that is \(t^2<48\).

What exam hint can help solve this Mathematics question?

वास्तविक मूल नहीं होने के लिए (D<0) होना चाहिए। इसलिए \(t^2-48<0\), अर्थात \(t^2<48\)।