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If (\sqrt{3}) is assumed rational and written as (\sqrt{3}=\frac{p}{q}), where (p) and (q) are coprime, where does the contradiction arise?
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Answer and explanation
Correct answer: Both (p) and (q) become divisible by (3)
From (\sqrt{3}=\frac{p}{q}), we get (p^2=3q^2), so both (p) and (q) become divisible by (3). In exams use the coprime condition at the end.
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What is the correct answer to this question?
Both (p) and (q) become divisible by (3)
Why is this the correct answer?
From (\sqrt{3}=\frac{p}{q}), we get (p^2=3q^2), so both (p) and (q) become divisible by (3). In exams use the coprime condition at the end.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
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