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If \(p(x)=x^2+ax+b\), \(p(2)=0\), and \(p(4)=0\), what is the value of \(a+b\)?

Answer and explanation

Correct answer: 2

Since \(p(2)=0\) and \(p(4)=0\), 2 and 4 are the zeros of the polynomial. Therefore, \(p(x)=(x-2)(x-4)=x^2-6x+8\). Comparing coefficients gives \(a=-6\) and \(b=8\), so \(a+b=-6+8=2\). Option 3 is not correct; the coefficients must be compared after factoring. Exam tip: if the zeros of a monic quadratic are \(r\) and \(s\), then \(p(x)=x^2-(r+s)x+rs\).

Related tags

Zeros Of PolynomialQuadratic PolynomialCoefficient ComparisonFactorisationPolynomials In One VariablePolynomialsMathematicsClass 10 Mcq

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