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If (p(x)=x^2-5), where will the graph (y=p(x)) cut the (x)-axis?
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Answer and explanation
Correct answer: (x=\pm\sqrt{5})
On the (x)-axis, (p(x)=0), so (x^2-5=0) gives (x=\pm\sqrt{5}). The (x)-intercepts are the zeroes.
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What is the correct answer to this question?
(x=\pm\sqrt{5})
Why is this the correct answer?
On the (x)-axis, (p(x)=0), so (x^2-5=0) gives (x=\pm\sqrt{5}). The (x)-intercepts are the zeroes.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
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