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If (p(x)=x^2-2x-2), what is the value of (p(\sqrt{2}))?
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Answer and explanation
Correct answer: (-2\sqrt{2})
(p(\sqrt{2})=(\sqrt{2})^2-2\sqrt{2}-2=2-2\sqrt{2}-2=-2\sqrt{2}). When substituting, write ((\sqrt{2})^2=2).
Frequently asked questions
What is the correct answer to this question?
(-2\sqrt{2})
Why is this the correct answer?
(p(\sqrt{2})=(\sqrt{2})^2-2\sqrt{2}-2=2-2\sqrt{2}-2=-2\sqrt{2}). When substituting, write ((\sqrt{2})^2=2).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
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