If \(p(x)=x^2-2x-2\), what is the product of its zeroes?
Answer and explanation
Correct answer: -2
For a quadratic \(ax^2+bx+c\) the product of the zeroes equals \(\dfrac{c}{a}\). Here \(a=1\) and \(c=-2\), so the product is \(\dfrac{-2}{1}=-2\). Option B (2) is incorrect due to wrong sign; options C (-1) and D (4) are numerically incorrect. Exam tip: remember product = \(c/a\) and always check the sign of \(c\).
Frequently asked questions
What is the correct answer to this question?
-2
Why is this the correct answer?
For a quadratic \(ax^2+bx+c\) the product of the zeroes equals \(\dfrac{c}{a}\). Here \(a=1\) and \(c=-2\), so the product is \(\dfrac{-2}{1}=-2\). Option B (2) is incorrect due to wrong sign; options C (-1) and D (4) are numerically incorrect. Exam tip: remember product = \(c/a\) and always check the sign of \(c\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
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