यदि AP में \(a_7=58\) और \(a_{16}+a_{25}=638\) है, तो \(a_{49}\) क्या होगा?
If in an AP \(a_7=58\) and \(a_{16}+a_{25}=638\), what is \(a_{49}\)?
Explanation opens after your attempt
Correct Answer
C. (808)
Concept
(a_{16}+a_{25}=\(a_7+9d\)+\(a_7+18d\)=116+27d=638), so \(d=\frac{58}{3}\) and \(a_{49}=58+42d=870\).
Why this answer is correct
The correct answer is C. (808). (a_{16}+a_{25}=\(a_7+9d\)+\(a_7+18d\)=116+27d=638), so \(d=\frac{58}{3}\) and \(a_{49}=58+42d=870\).
Exam Tip
(a_{16}+a_{25}=\(a_7+9d\)+\(a_7+18d\)=116+27d=638), इसलिए \(d=\frac{58}{3}\) और \(a_{49}=58+42d=870\)।
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