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ap expert mixed equation MCQ Questions for Class 10

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3 questions tagged with ap expert mixed equation.

Question 1/3 Expert Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 66

यदि AP में \(a_7=58\) और \(a_{16}+a_{25}=638\) है, तो \(a_{49}\) क्या होगा?

If in an AP \(a_7=58\) and \(a_{16}+a_{25}=638\), what is \(a_{49}\)?

Explanation opens after your attempt
Correct Answer

C. (808)

Step 1

Concept

(a_{16}+a_{25}=\(a_7+9d\)+\(a_7+18d\)=116+27d=638), so \(d=\frac{58}{3}\) and \(a_{49}=58+42d=870\).

Step 2

Why this answer is correct

The correct answer is C. (808). (a_{16}+a_{25}=\(a_7+9d\)+\(a_7+18d\)=116+27d=638), so \(d=\frac{58}{3}\) and \(a_{49}=58+42d=870\).

Step 3

Exam Tip

(a_{16}+a_{25}=\(a_7+9d\)+\(a_7+18d\)=116+27d=638), इसलिए \(d=\frac{58}{3}\) और \(a_{49}=58+42d=870\)।

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Question 2/3 Expert Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 65

यदि AP में \(a_6=42\) और \(a_{14}+a_{22}=420\) है, तो \(a_{38}\) क्या होगा?

If in an AP \(a_6=42\) and \(a_{14}+a_{22}=420\), what is \(a_{38}\)?

Explanation opens after your attempt
Correct Answer

B. (462)

Step 1

Concept

(a_{14}+a_{22}=\(a_6+8d\)+\(a_6+16d\)=84+24d=420), so (d=14). \(a_{38}=42+32d=490\), which is not in the options.

Step 2

Why this answer is correct

The correct answer is B. (462). (a_{14}+a_{22}=\(a_6+8d\)+\(a_6+16d\)=84+24d=420), so (d=14). \(a_{38}=42+32d=490\), which is not in the options.

Step 3

Exam Tip

(a_{14}+a_{22}=\(a_6+8d\)+\(a_6+16d\)=84+24d=420), इसलिए (d=14)। \(a_{38}=42+32d=490\), विकल्पों में यह नहीं है।

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Question 3/3 Expert Mathematics Arithmetic Progressions (AP) Finding the $n$th term of an AP Class 10 Level 65

यदि समान्तर श्रेणी में \(a_5=31\) और \(a_{12}+a_{19}=272\) है, तो \(a_{33}\) क्या होगा?

If in an AP \(a_5=31\) and \(a_{12}+a_{19}=272\), what is \(a_{33}\)?

Explanation opens after your attempt
Correct Answer

C. (311)

Step 1

Concept

\(a_{12}+a_{19}=62+21d=272\), so (d=10). \(a_{33}=31+28\times10=311\).

Step 2

Why this answer is correct

The correct answer is C. (311). \(a_{12}+a_{19}=62+21d=272\), so (d=10). \(a_{33}=31+28\times10=311\).

Step 3

Exam Tip

\(a_{12}+a_{19}=62+21d=272\), इसलिए (d=10)। \(a_{33}=31+28\times10=311\)।

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