In an AP, a₆ = 42 and a₁₄ + a₂₂ = 420. What is a₃₈?एक AP में a₆ = 42 और a₁₄ + a₂₂ = 420 है। a₃₈ का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 490490
Using aₙ = a₆ + (n − 6)d, we get a₁₄ + a₂₂ = (42 + 8d) + (42 + 16d) = 84 + 24d = 420, so d = 14. Therefore, a₃₈ = 42 + 32(14) = 490.aₙ = a₆ + (n − 6)d का उपयोग करने पर a₁₄ + a₂₂ = (42 + 8d) + (42 + 16d) = 84 + 24d = 420 मिलता है, इसलिए d = 14। अतः a₃₈ = 42 + 32(14) = 490।
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