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If assuming (\sqrt{3}=\frac{p}{q}) gives (p^2=3q^2), what is the main purpose of showing divisibility by (3) for both (p) and (q) in the proof?

Answer and explanation

Correct answer: To show a contradiction with coprimality of the lowest-form fraction

Step 1: Assuming (\sqrt{3}) rational, (\frac{p}{q}) is taken in lowest form. Step 2: The proof gives (3\mid p) and (3\mid q), so (3) is a common factor of both. Step 3: A lowest-form fraction cannot have a common factor, so (\sqrt{3}) is proved irrational.

Related tags

Real-NumbersRoot3CoprimeContradictionExpertProof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real Numbers

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