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What is the final contradiction in the proof of (\sqrt{2})?

Answer and explanation

Correct answer: Both (p) and (q) are found even

Step 1: At the start, (p) and (q) were assumed coprime. Step 2: The proof shows both (p) and (q) are even, so they have common factor (2). Step 3: This contradiction shows that (\sqrt{2}) is not rational.

Related tags

ContradictionSqrt2 ProofClass 10Proof Of Irrationality Of √2√3√5Proof Of Irrationality Of 2 3 5Real NumbersMathematicsClass 10 Mcq

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