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If (\alpha) and (\beta) are zeroes of (x^2-2x-11), what is (\alpha^2+\beta^2+\alpha\beta)?
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Answer and explanation
Correct answer: (15)
(\alpha+\beta=2) and (\alpha\beta=-11), so (\alpha^2+\beta^2+\alpha\beta=(\alpha+\beta)^2-\alpha\beta=4+11=15). Sum and product are enough for symmetric expressions.
Frequently asked questions
What is the correct answer to this question?
(15)
Why is this the correct answer?
(\alpha+\beta=2) and (\alpha\beta=-11), so (\alpha^2+\beta^2+\alpha\beta=(\alpha+\beta)^2-\alpha\beta=4+11=15). Sum and product are enough for symmetric expressions.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Irrational numbers and real numbers.
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