If \(a\neq 0\), what is the simplest form of \(\frac{(a^4)^3}{a^5}\)?

Correct answer: a⁷

Use the power-of-a-power law \((a^m)^n=a^{mn}\) and the quotient law for equal bases, \(a^m\div a^n=a^{m-n}\). Thus, \(\frac{(a^4)^3}{a^5}=\frac{a^{12}}{a^5}=a^{12-5}=a^7\). Therefore, option B is correct. Option C stops after applying the power-of-a-power rule, while option D incorrectly adds the exponents during division. In an exam, multiply exponents inside a power first and subtract exponents when dividing like bases.