समीकरण (x-2-(a+b)x+ab=0) के मूल समान कब होंगे?
When will the roots of (x-2-(a+b)x+ab=0) be equal?
Explanation opens after your attempt
Step 1
Concept
Here (D=(a+b)2-4ab=(a-b)2). For equal roots (D=0), hence (a=b).
Step 2
Why this answer is correct
The correct answer is A. (a=b). Here (D=(a+b)2-4ab=(a-b)2). For equal roots (D=0), hence (a=b).
Step 3
Exam Tip
यहाँ (D=(a+b)2-4ab=(a-b)2) है। समान मूलों के लिए (D=0), अतः (a=b)।
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यदि (7x-2-(p+6)x+28=0) के मूल (2) और (2) हैं, तो (p) क्या होगा?
If the roots of (7x-2-(p+6)x+28=0) are (2) and (2), what is (p)?
Explanation opens after your attempt
Step 1
Concept
The sum of roots is (4), and \(\frac{p+6}{7}=4\), so (p=22). In exams, use \(-\frac{b}{a}\) for the sum.
Step 2
Why this answer is correct
The correct answer is A. (p=22). The sum of roots is (4), and \(\frac{p+6}{7}=4\), so (p=22). In exams, use \(-\frac{b}{a}\) for the sum.
Step 3
Exam Tip
मूलों का योग (4) है और \(\frac{p+6}{7}=4\), इसलिए (p=22) है। परीक्षा में \(-\frac{b}{a}\) से योग निकालें।
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यदि (6x-2-(p+5)x+24=0) के मूल (2) और (2) हैं, तो (p) क्या होगा?
If the roots of (6x-2-(p+5)x+24=0) are (2) and (2), what is (p)?
Explanation opens after your attempt
Step 1
Concept
The sum of roots is (4), and \(\frac{p+5}{6}=4\), so (p=19). In exams, use \(-\frac{b}{a}\) for the sum.
Step 2
Why this answer is correct
The correct answer is A. (p=19). The sum of roots is (4), and \(\frac{p+5}{6}=4\), so (p=19). In exams, use \(-\frac{b}{a}\) for the sum.
Step 3
Exam Tip
मूलों का योग (4) है और \(\frac{p+5}{6}=4\), इसलिए (p=19) है। परीक्षा में \(-\frac{b}{a}\) से योग निकालें।
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यदि (5x-2-(p+4)x+20=0) के मूल (2) और (2) हैं, तो (p) क्या होगा?
If the roots of (5x-2-(p+4)x+20=0) are (2) and (2), what is (p)?
Explanation opens after your attempt
Step 1
Concept
The sum of roots is (4), and \(\frac{p+4}{5}=4\), so (p=16). In exams, use \(-\frac{b}{a}\) for the sum.
Step 2
Why this answer is correct
The correct answer is A. (p=16). The sum of roots is (4), and \(\frac{p+4}{5}=4\), so (p=16). In exams, use \(-\frac{b}{a}\) for the sum.
Step 3
Exam Tip
मूलों का योग (4) है और \(\frac{p+4}{5}=4\), इसलिए (p=16) है। परीक्षा में \(-\frac{b}{a}\) से योग निकालें।
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यदि (4x-2-(p-1)x+9=0) के मूल \(\frac{3}{2}\) और \(\frac{3}{2}\) हैं, तो (p) क्या होगा?
If the roots of (4x-2-(p-1)x+9=0) are \(\frac{3}{2}\) and \(\frac{3}{2}\), what is (p)?
Explanation opens after your attempt
Step 1
Concept
The sum of roots is (3), and \(\frac{p-1}{4}=3\), so (p=13). In exams, use \(-\frac{b}{a}\) for the sum of roots.
Step 2
Why this answer is correct
The correct answer is A. (p=13). The sum of roots is (3), and \(\frac{p-1}{4}=3\), so (p=13). In exams, use \(-\frac{b}{a}\) for the sum of roots.
Step 3
Exam Tip
मूलों का योग (3) है और \(\frac{p-1}{4}=3\), इसलिए (p=13) है। परीक्षा में मूलों का योग \(-\frac{b}{a}\) से लें।
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यदि (3x-2-(p+2)x+12=0) के मूल (2) और (2) हैं, तो (p) क्या होगा?
If the roots of (3x-2-(p+2)x+12=0) are (2) and (2), what is (p)?
Explanation opens after your attempt
Step 1
Concept
The sum of roots is (4), and \(\frac{p+2}{3}=4\), so (p=10). In exams, find the sum of roots using \(-\frac{b}{a}\).
Step 2
Why this answer is correct
The correct answer is A. (p=10). The sum of roots is (4), and \(\frac{p+2}{3}=4\), so (p=10). In exams, find the sum of roots using \(-\frac{b}{a}\).
Step 3
Exam Tip
मूलों का योग (4) है और \(\frac{p+2}{3}=4\), इसलिए (p=10) है। परीक्षा में मूलों का योग \(-\frac{b}{a}\) से निकालें।
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यदि (2x-2-(p+3)x+8=0) के मूल (2) और (4) हैं, तो (p) क्या होगा?
If the roots of (2x-2-(p+3)x+8=0) are (2) and (4), what is (p)?
Explanation opens after your attempt
Step 1
Concept
The sum of roots is (2+4=6), and \(\frac{p+3}{2}=6\), so (p=9). In exams, use \(-\frac{b}{a}\) for sum of roots.
Step 2
Why this answer is correct
The correct answer is A. (p=9). The sum of roots is (2+4=6), and \(\frac{p+3}{2}=6\), so (p=9). In exams, use \(-\frac{b}{a}\) for sum of roots.
Step 3
Exam Tip
मूलों का योग (2+4=6) है और \(\frac{p+3}{2}=6\), इसलिए (p=9) है। परीक्षा में \( -\frac{b}{a}\) से मूलों का योग लें।
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