किस स्थिति में असमानता का चिन्ह उलट जाता है?
In which situation does the inequality sign reverse?
#linear inequalities
#introduction
#class 11
A दोनों पक्षों को ऋणात्मक संख्या से गुणा करने पर / When both sides are multiplied by a negative number
B दोनों पक्षों में समान संख्या जोड़ने पर / When the same number is added to both sides
C दोनों पक्षों से समान संख्या घटाने पर / When the same number is subtracted from both sides
D दोनों पक्षों को धनात्मक संख्या से भाग देने पर / When both sides are divided by a positive number
Explanation opens after your attempt
Correct Answer
A. दोनों पक्षों को ऋणात्मक संख्या से गुणा करने पर / When both sides are multiplied by a negative number
Step 1
Concept
Multiplying or dividing by a negative number reverses the inequality direction. This is the most common mistake in linear inequalities.
Step 2
Why this answer is correct
The correct answer is A. दोनों पक्षों को ऋणात्मक संख्या से गुणा करने पर / When both sides are multiplied by a negative number. Multiplying or dividing by a negative number reverses the inequality direction. This is the most common mistake in linear inequalities.
Step 3
Exam Tip
ऋणात्मक संख्या से गुणा या भाग करने पर असमानता की दिशा बदलती है। यह रैखिक असमानताओं में सबसे सामान्य गलती है।
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असमानता (2(3x+1)\geq 4x+10) का हल चुनिए।
Choose the solution of (2(3x+1)\geq 4x+10).
#linear inequalities
#introduction
#class 11
A \(x\geq 4\)
B \(x\leq 4\)
C (x>4)
D (x<4)
Explanation opens after your attempt
Correct Answer
A. \(x\geq 4\)
Step 1
Concept
\(6x+2\geq 4x+10\) gives \(2x\geq 8\), so \(x\geq 4\). Multiply every term while opening brackets.
Step 2
Why this answer is correct
The correct answer is A. \(x\geq 4\). \(6x+2\geq 4x+10\) gives \(2x\geq 8\), so \(x\geq 4\). Multiply every term while opening brackets.
Step 3
Exam Tip
\(6x+2\geq 4x+10\) से \(2x\geq 8\), इसलिए \(x\geq 4\)। कोष्ठक खोलते समय हर पद पर गुणा करें।
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असमानता (3(x-2)>12) का हल क्या होगा?
What will be the solution of (3(x-2)>12)?
#linear inequalities
#introduction
#class 11
A (x>6)
B (x<6)
C (x>4)
D (x<4)
Explanation opens after your attempt
Step 1
Concept
From (x-2>4), we get (x>6). Expanding brackets or dividing by positive (3) both work.
Step 2
Why this answer is correct
The correct answer is A. (x>6). From (x-2>4), we get (x>6). Expanding brackets or dividing by positive (3) both work.
Step 3
Exam Tip
(x-2>4) से (x>6) मिलता है। पहले कोष्ठक खोलना या धनात्मक (3) से भाग देना दोनों सही हैं।
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असमानता \(6x+1\leq 2x+17\) का सबसे बड़ा पूर्णांक हल क्या है?
What is the greatest integer solution of \(6x+1\leq 2x+17\)?
#linear inequalities
#introduction
#class 11
A (4)
B (5)
C (3)
D (6)
Explanation opens after your attempt
Step 1
Concept
From \(4x\leq 16\), we get \(x\leq 4\). Hence the greatest integer solution is (4).
Step 2
Why this answer is correct
The correct answer is A. (4). From \(4x\leq 16\), we get \(x\leq 4\). Hence the greatest integer solution is (4).
Step 3
Exam Tip
\(4x\leq 16\) से \(x\leq 4\) मिलता है। इसलिए सबसे बड़ा पूर्णांक हल (4) है।
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कौन सा चिह्न कठोर असमानता को दर्शाता है?
Which symbol represents a strict inequality?
#linear inequalities
#introduction
#class 11
A
B \(\leq\)
C \(\geq\)
D
Explanation opens after your attempt
Step 1
Concept
(<) and (>) are strict inequalities because equality is not included. \(\leq\) and \(\geq\) include equality.
Step 2
Why this answer is correct
The correct answer is A. . (<) and (>) are strict inequalities because equality is not included. \(\leq\) and \(\geq\) include equality.
Step 3
Exam Tip
(<) और (>) कठोर असमानताएं हैं क्योंकि बराबरी शामिल नहीं होती। \(\leq\) और \(\geq\) में बराबरी शामिल होती है।
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यदि (x) वास्तविक संख्या है, तो \(x^2\geq 0\) किस प्रकार का कथन है?
If (x) is a real number, what type of statement is \(x^2\geq 0\)?
#linear inequalities
#introduction
#class 11
A हमेशा सत्य / Always true
B हमेशा असत्य / Always false
C केवल (x>0) पर सत्य / True only for (x>0)
D केवल (x<0) पर सत्य / True only for (x<0)
Explanation opens after your attempt
Correct Answer
A. हमेशा सत्य / Always true
Step 1
Concept
The square of any real number is never negative. This is a basic inequality concept.
Step 2
Why this answer is correct
The correct answer is A. हमेशा सत्य / Always true. The square of any real number is never negative. This is a basic inequality concept.
Step 3
Exam Tip
किसी भी वास्तविक संख्या का वर्ग ऋणात्मक नहीं होता। यह मूलभूत असमानता अवधारणा है।
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असमानता (4x-5<2x+7) का हल क्या है?
What is the solution of (4x-5<2x+7)?
#linear inequalities
#introduction
#class 11
A (x<6)
B (x>6)
C \(x\leq 6\)
D \(x\geq 6\)
Explanation opens after your attempt
Step 1
Concept
From (2x<12), we get (x<6). Combine like terms to form a simple linear inequality.
Step 2
Why this answer is correct
The correct answer is A. (x<6). From (2x<12), we get (x<6). Combine like terms to form a simple linear inequality.
Step 3
Exam Tip
(2x<12) से (x<6) मिलता है। समान पदों को मिलाकर सरल रैखिक असमानता बनाएं।
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कौन सा अंतराल \(x\geq -2\) को दर्शाता है?
Which interval represents \(x\geq -2\)?
#linear inequalities
#introduction
#class 11
A \([-2,\infty\))
B (\(-2,\infty\))
C (\(-\infty,-2]\)
D (\(-\infty,-2\))
Explanation opens after your attempt
Correct Answer
A. \([-2,\infty\))
Step 1
Concept
In \(x\geq -2\), (-2) is included and values go to the right. So \([-2,\infty\)) is correct.
Step 2
Why this answer is correct
The correct answer is A. \([-2,\infty\)). In \(x\geq -2\), (-2) is included and values go to the right. So \([-2,\infty\)) is correct.
Step 3
Exam Tip
\(x\geq -2\) में (-2) शामिल है और मान दाईं ओर जाते हैं। इसलिए \([-2,\infty\)) सही है।
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असमानता \(-3\leq x+2<8\) को हल कीजिए।
Solve the inequality \(-3\leq x+2<8\).
#linear inequalities
#introduction
#class 11
A \(-5\leq x<6\)
B \(-1\leq x<10\)
C \(-5<x\leq 6\)
D \(-6\leq x<5\)
Explanation opens after your attempt
Correct Answer
A. \(-5\leq x<6\)
Step 1
Concept
Subtracting (2) from all parts gives \(-5\leq x<6\). The equality sign remains on the same boundary.
Step 2
Why this answer is correct
The correct answer is A. \(-5\leq x<6\). Subtracting (2) from all parts gives \(-5\leq x<6\). The equality sign remains on the same boundary.
Step 3
Exam Tip
सभी भागों से (2) घटाने पर \(-5\leq x<6\) मिलता है। बराबरी वाला चिन्ह उसी तरफ बना रहता है।
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संयुक्त असमानता \(1<2x+3\leq 11\) का हल क्या है?
What is the solution of the compound inequality \(1<2x+3\leq 11\)?
#linear inequalities
#introduction
#class 11
A \(-1<x\leq 4\)
B \(-1\leq x<4\)
C \(1<x\leq 4\)
D \(-4<x\leq 1\)
Explanation opens after your attempt
Correct Answer
A. \(-1<x\leq 4\)
Step 1
Concept
Subtracting (3) from all parts gives \(-2<2x\leq 8\), so \(-1<x\leq 4\). Handle both bounds together in compound inequalities.
Step 2
Why this answer is correct
The correct answer is A. \(-1<x\leq 4\). Subtracting (3) from all parts gives \(-2<2x\leq 8\), so \(-1<x\leq 4\). Handle both bounds together in compound inequalities.
Step 3
Exam Tip
सभी भागों से (3) घटाने पर \(-2<2x\leq 8\), इसलिए \(-1<x\leq 4\)। संयुक्त असमानता में दोनों सीमाएं साथ संभालें।
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किस असमानता का हल (\(-\infty,6\)) है?
Which inequality has the solution (\(-\infty,6\))?
#linear inequalities
#introduction
#class 11
A (x<6)
B \(x\leq 6\)
C (x>6)
D \(x\geq 6\)
Explanation opens after your attempt
Step 1
Concept
(\(-\infty,6\)) means all real values less than (6). Since (6) is not included, (x<6) is correct.
Step 2
Why this answer is correct
The correct answer is A. (x<6). (\(-\infty,6\)) means all real values less than (6). Since (6) is not included, (x<6) is correct.
Step 3
Exam Tip
(\(-\infty,6\)) का अर्थ (6) से छोटे सभी वास्तविक मान हैं। (6) शामिल नहीं है, इसलिए (x<6) सही है।
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यदि \(\frac{x-1}{2}\geq 4\), तो (x) का न्यूनतम पूर्णांक मान क्या है?
If \(\frac{x-1}{2}\geq 4\), what is the least integer value of (x)?
#linear inequalities
#introduction
#class 11
A (9)
B (8)
C (7)
D (10)
Explanation opens after your attempt
Step 1
Concept
From \(\frac{x-1}{2}\geq 4\), we get \(x\geq 9\). Hence the least integer is (9).
Step 2
Why this answer is correct
The correct answer is A. (9). From \(\frac{x-1}{2}\geq 4\), we get \(x\geq 9\). Hence the least integer is (9).
Step 3
Exam Tip
\(\frac{x-1}{2}\geq 4\) से \(x\geq 9\) मिलता है। इसलिए न्यूनतम पूर्णांक (9) है।
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असमानता \(\frac{x}{3}+2<5\) का हल कौन सा है?
Which is the solution of \(\frac{x}{3}+2<5\)?
#linear inequalities
#introduction
#class 11
A (x<9)
B (x>9)
C \(x\leq 9\)
D \(x\geq 9\)
Explanation opens after your attempt
Step 1
Concept
\(\frac{x}{3}<3\), so (x<9). Multiplying by positive (3) does not change the sign.
Step 2
Why this answer is correct
The correct answer is A. (x<9). \(\frac{x}{3}<3\), so (x<9). Multiplying by positive (3) does not change the sign.
Step 3
Exam Tip
\(\frac{x}{3}<3\) इसलिए (x<9) है। धनात्मक (3) से गुणा करने पर चिन्ह नहीं बदलता।
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असमानता \(7x+3\geq 3x+15\) का हल क्या है?
What is the solution of \(7x+3\geq 3x+15\)?
#linear inequalities
#introduction
#class 11
A \(x\geq 3\)
B \(x\leq 3\)
C (x>3)
D (x<3)
Explanation opens after your attempt
Correct Answer
A. \(x\geq 3\)
Step 1
Concept
From \(4x\geq 12\), we get \(x\geq 3\). Bringing variable terms to one side is a simple method.
Step 2
Why this answer is correct
The correct answer is A. \(x\geq 3\). From \(4x\geq 12\), we get \(x\geq 3\). Bringing variable terms to one side is a simple method.
Step 3
Exam Tip
\(4x\geq 12\) से \(x\geq 3\) मिलता है। चर वाले पदों को एक तरफ लाना सरल तरीका है।
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यदि \(x\in\mathbb{N}\) और (x<5), तो हल समुच्चय क्या होगा?
If \(x\in\mathbb{N}\) and (x<5), what is the solution set?
#linear inequalities
#introduction
#class 11
A ({1,2,3,4})
B ({0,1,2,3,4})
C ({1,2,3,4,5})
D (\(-\infty,5\))
Explanation opens after your attempt
Correct Answer
A. ({1,2,3,4})
Step 1
Concept
Usually, \(\mathbb{N}\) means \(1,2,3,\ldots\). Thus the natural numbers less than (5) are ({1,2,3,4}).
Step 2
Why this answer is correct
The correct answer is A. ({1,2,3,4}). Usually, \(\mathbb{N}\) means \(1,2,3,\ldots\). Thus the natural numbers less than (5) are ({1,2,3,4}).
Step 3
Exam Tip
\(\mathbb{N}\) में सामान्यतः \(1,2,3,\ldots\) लिए जाते हैं। इसलिए (5) से छोटे प्राकृतिक मान ({1,2,3,4}) हैं।
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कौन सा मान (2x+1<9) का हल नहीं है?
Which value is not a solution of (2x+1<9)?
#linear inequalities
#introduction
#class 11
A (x=4)
B (x=0)
C (x=-2)
D (x=3)
Explanation opens after your attempt
Step 1
Concept
The inequality gives (x<4), so (x=4) is not included. In a strict inequality, the boundary value is not a solution.
Step 2
Why this answer is correct
The correct answer is A. (x=4). The inequality gives (x<4), so (x=4) is not included. In a strict inequality, the boundary value is not a solution.
Step 3
Exam Tip
असमानता से (x<4) मिलता है, इसलिए (x=4) शामिल नहीं है। कठोर असमानता में सीमा मान हल नहीं होता।
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असमानता \(5-2x\geq 1\) को हल कीजिए।
Solve the inequality \(5-2x\geq 1\).
#linear inequalities
#introduction
#class 11
A \(x\leq 2\)
B \(x\geq 2\)
C (x<2)
D (x>2)
Explanation opens after your attempt
Correct Answer
A. \(x\leq 2\)
Step 1
Concept
\(-2x\geq -4\), and dividing by a negative gives \(x\leq 2\). Reversing the sign is the key step here.
Step 2
Why this answer is correct
The correct answer is A. \(x\leq 2\). \(-2x\geq -4\), and dividing by a negative gives \(x\leq 2\). Reversing the sign is the key step here.
Step 3
Exam Tip
\(-2x\geq -4\) और ऋणात्मक से भाग देने पर \(x\leq 2\) मिलता है। ऐसे प्रश्नों में चिन्ह पलटना सबसे महत्वपूर्ण है।
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असमानता \(x-4\geq 6\) का हल समुच्चय क्या है?
What is the solution set of \(x-4\geq 6\)?
#linear inequalities
#introduction
#class 11
A \([10,\infty\))
B (\(10,\infty\))
C (\(-\infty,10]\)
D (\(-\infty,10\))
Explanation opens after your attempt
Correct Answer
A. \([10,\infty\))
Step 1
Concept
We get \(x\geq 10\), so the interval is \([10,\infty\)). With \(\geq\), (10) is included.
Step 2
Why this answer is correct
The correct answer is A. \([10,\infty\)). We get \(x\geq 10\), so the interval is \([10,\infty\)). With \(\geq\), (10) is included.
Step 3
Exam Tip
\(x\geq 10\) मिलता है, इसलिए अंतराल \([10,\infty\)) है। \(\geq\) होने पर (10) शामिल रहेगा।
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अंतराल ((2,7]) को असमानता के रूप में कैसे लिखेंगे?
How will the interval ((2,7]) be written as an inequality?
#linear inequalities
#introduction
#class 11
A \(2<x\leq 7\)
B \(2\leq x<7\)
C (2<x<7)
D \(2\leq x\leq 7\)
Explanation opens after your attempt
Correct Answer
A. \(2<x\leq 7\)
Step 1
Concept
In ((2,7]), (2) is not included and (7) is included. Identify open and closed brackets carefully.
Step 2
Why this answer is correct
The correct answer is A. \(2<x\leq 7\). In ((2,7]), (2) is not included and (7) is included. Identify open and closed brackets carefully.
Step 3
Exam Tip
((2,7]) में (2) शामिल नहीं और (7) शामिल है। खुले और बंद कोष्ठक को ध्यान से पहचानें।
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यदि (-4x<20), तो सही हल क्या होगा?
If (-4x<20), what is the correct solution?
#linear inequalities
#introduction
#class 11
A (x>-5)
B (x<-5)
C (x>5)
D (x<5)
Explanation opens after your attempt
Step 1
Concept
Dividing by the negative number (-4) reverses the inequality sign. Hence (x>-5) is correct.
Step 2
Why this answer is correct
The correct answer is A. (x>-5). Dividing by the negative number (-4) reverses the inequality sign. Hence (x>-5) is correct.
Step 3
Exam Tip
ऋणात्मक संख्या (-4) से भाग देने पर असमानता का चिन्ह बदलता है। इसलिए (x>-5) सही है।
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असमानता \(2x-7\leq 9\) का हल चुनिए।
Choose the solution of the inequality \(2x-7\leq 9\).
#linear inequalities
#introduction
#class 11
A \(x\leq 8\)
B \(x\geq 8\)
C (x<8)
D (x>8)
Explanation opens after your attempt
Correct Answer
A. \(x\leq 8\)
Step 1
Concept
Since \(2x\leq 16\), \(x\leq 8\). In \(\leq\), the boundary value is included.
Step 2
Why this answer is correct
The correct answer is A. \(x\leq 8\). Since \(2x\leq 16\), \(x\leq 8\). In \(\leq\), the boundary value is included.
Step 3
Exam Tip
\(2x\leq 16\) इसलिए \(x\leq 8\) है। \(\leq\) में सीमा भी हल में शामिल होती है।
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असमानता (3x+5>14) का हल कौन सा है?
What is the solution of the inequality (3x+5>14)?
#linear inequalities
#introduction
#class 11
A (x>3)
B (x<3)
C \(x\geq 3\)
D \(x\leq 3\)
Explanation opens after your attempt
Step 1
Concept
From (3x>9), we get (x>3). In exams, subtracting the same number from both sides keeps the sign unchanged.
Step 2
Why this answer is correct
The correct answer is A. (x>3). From (3x>9), we get (x>3). In exams, subtracting the same number from both sides keeps the sign unchanged.
Step 3
Exam Tip
(3x>9) से (x>3) मिलता है। परीक्षा में दोनों पक्षों से समान संख्या घटाना सुरक्षित रहता है।
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यदि (f(x)=3x-2 ) और (g(x)=2x-2 +1), तो ((f+g)(x)) किसके बराबर है?
If (f(x)=3x-2 ) and (g(x)=2x-2 +1), then ((f+g)(x)) is equal to which expression?
#algebra
#real functions
#polynomial addition
#class 11
A \(5x^2+1\)
B \(6x^4+1\)
C \(x^2+1\)
D \(5x^4\)
Explanation opens after your attempt
Correct Answer
A. \(5x^2+1\)
Step 1
Concept
((f+g)(x)=3x-2 +2x-2 +1=5x-2 +1). Add terms with the same power.
Step 2
Why this answer is correct
The correct answer is A. \(5x^2+1\). ((f+g)(x)=3x-2 +2x-2 +1=5x-2 +1). Add terms with the same power.
Step 3
Exam Tip
((f+g)(x)=3x-2 +2x-2 +1=5x-2 +1)। समान घात वाले पद जोड़ें।
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यदि (f(x)=x-2 -1) और (g(x)=x-2 +1), तो ((f+g)(x)) क्या है?
If (f(x)=x-2 -1) and (g(x)=x-2 +1), what is ((f+g)(x))?
#algebra
#real functions
#polynomial addition
#class 11
A \(2x^2\)
B (2)
C \(x^4-1\)
D \(2x^2+2\)
Explanation opens after your attempt
Correct Answer
A. \(2x^2\)
Step 1
Concept
((f+g)(x)=x-2 -1+x-2 +1=2x-2 ). The constant terms (-1) and (1) cancel out.
Step 2
Why this answer is correct
The correct answer is A. \(2x^2\). ((f+g)(x)=x-2 -1+x-2 +1=2x-2 ). The constant terms (-1) and (1) cancel out.
Step 3
Exam Tip
((f+g)(x)=x-2 -1+x-2 +1=2x-2 )। स्थिर पद (-1) और (1) कट जाते हैं।
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यदि (f(x)=x-2 +2x) और (g(x)=x-2 -x), तो ((f-g)(x)) क्या है?
If (f(x)=x-2 +2x) and (g(x)=x-2 -x), what is ((f-g)(x))?
#algebra
#real functions
#polynomial subtraction
#class 11
A (3x)
B \(2x^2+x\)
C (x)
D \(x^2+3x\)
Explanation opens after your attempt
Step 1
Concept
((f-g)(x)=x-2 +2x-\(x^2-x\)=3x). The like \(x^2\) terms cancel out.
Step 2
Why this answer is correct
The correct answer is A. (3x). ((f-g)(x)=x-2 +2x-\(x^2-x\)=3x). The like \(x^2\) terms cancel out.
Step 3
Exam Tip
((f-g)(x)=x-2 +2x-\(x^2-x\)=3x)। समान \(x^2\) पद कट जाते हैं।
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यदि (f(x)=x+4), तो ((2f)(x)) क्या होगा?
If (f(x)=x+4), what is ((2f)(x))?
#algebra
#real functions
#scalar multiplication
#class 11
A (2x+8)
B (x+8)
C (2x+4)
D (x+6)
Explanation opens after your attempt
Step 1
Concept
((2f)(x)=2f(x)=2(x+4)=2x+8). In scalar multiplication, multiply every term.
Step 2
Why this answer is correct
The correct answer is A. (2x+8). ((2f)(x)=2f(x)=2(x+4)=2x+8). In scalar multiplication, multiply every term.
Step 3
Exam Tip
((2f)(x)=2f(x)=2(x+4)=2x+8)। स्थिर गुणन में हर पद से गुणा करें।
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यदि (f(x)=x-2 ) और (g(x)=4), तो ((f+g)(2)) का मान क्या है?
If (f(x)=x-2 ) and (g(x)=4), what is the value of ((f+g)(2))?
#algebra
#real functions
#value based
#class 11
A (8)
B (6)
C (12)
D (4)
Explanation opens after your attempt
Step 1
Concept
((f+g)(2)=f(2)+g(2)=4+4=8). You may add functions first or substitute directly.
Step 2
Why this answer is correct
The correct answer is A. (8). ((f+g)(2)=f(2)+g(2)=4+4=8). You may add functions first or substitute directly.
Step 3
Exam Tip
((f+g)(2)=f(2)+g(2)=4+4=8)। पहले फलन जोड़ें या सीधे मान रखें।
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यदि (f(x)=2x+6) और (g(x)=2), तो (\left\(\frac{f}{g}\right\)(x)) क्या होगा?
If (f(x)=2x+6) and (g(x)=2), what is (\left\(\frac{f}{g}\right\)(x))?
#algebra
#real functions
#function quotient
#class 11
A (x+3)
B (2x+3)
C (x+6)
D (4x+12)
Explanation opens after your attempt
Step 1
Concept
In division, (\left\(\frac{f}{g}\right\)(x)=\frac{2x+6}{2}=x+3). The denominator must not be zero.
Step 2
Why this answer is correct
The correct answer is A. (x+3). In division, (\left\(\frac{f}{g}\right\)(x)=\frac{2x+6}{2}=x+3). The denominator must not be zero.
Step 3
Exam Tip
भाग में (\left\(\frac{f}{g}\right\)(x)=\frac{2x+6}{2}=x+3)। हर शून्य नहीं होना चाहिए।
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यदि (f(x)=x+1) और (g(x)=x-1), तो ((fg)(x)) क्या है?
If (f(x)=x+1) and (g(x)=x-1), what is ((fg)(x))?
#algebra
#real functions
#function product
#class 11
A \(x^2-1\)
B \(x^2+1\)
C (2x)
D \(x^2-2x+1\)
Explanation opens after your attempt
Correct Answer
A. \(x^2-1\)
Step 1
Concept
In multiplication, ((fg)(x)=f(x)g(x)), so ((x+1)(x-1)=x-2 -1). Remember the identity \(a^2-b^2\).
Step 2
Why this answer is correct
The correct answer is A. \(x^2-1\). In multiplication, ((fg)(x)=f(x)g(x)), so ((x+1)(x-1)=x-2 -1). Remember the identity \(a^2-b^2\).
Step 3
Exam Tip
गुणन में ((fg)(x)=f(x)g(x)), इसलिए ((x+1)(x-1)=x-2 -1)। पहचान \(a^2-b^2\) याद रखें।
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यदि (f(x)=5x-1) और (g(x)=2x+4), तो ((f-g)(x)) ज्ञात कीजिए।
If (f(x)=5x-1) and (g(x)=2x+4), find ((f-g)(x)).
#algebra
#real functions
#function subtraction
#class 11
A (3x-5)
B (7x+3)
C (3x+5)
D (7x-5)
Explanation opens after your attempt
Step 1
Concept
((f-g)(x)=(5x-1)-(2x+4)=3x-5). In subtraction, change every sign of the second function.
Step 2
Why this answer is correct
The correct answer is A. (3x-5). ((f-g)(x)=(5x-1)-(2x+4)=3x-5). In subtraction, change every sign of the second function.
Step 3
Exam Tip
((f-g)(x)=(5x-1)-(2x+4)=3x-5)। घटाने में दूसरे फलन के सभी चिह्न बदलें।
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