असमानता \(6x+1\leq 2x+17\) का सबसे बड़ा पूर्णांक हल क्या है?
What is the greatest integer solution of \(6x+1\leq 2x+17\)?
Explanation opens after your attempt
A. (4)
Concept
From \(4x\leq 16\), we get \(x\leq 4\). Hence the greatest integer solution is (4).
Why this answer is correct
The correct answer is A. (4). From \(4x\leq 16\), we get \(x\leq 4\). Hence the greatest integer solution is (4).
Exam Tip
\(4x\leq 16\) से \(x\leq 4\) मिलता है। इसलिए सबसे बड़ा पूर्णांक हल (4) है।
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