असमानता (5x-4<3x+2) का हल क्या है?
What is the solution of (5x-4<3x+2)?
#linear-inequalities
#variables-both-sides
#class-11
#easy
A (x<3)
B (x>3)
C (x< -3)
D (x> -3)
Explanation opens after your attempt
Step 1
Concept
From (5x-4<3x+2), we get (2x<6), so (x<3). Combining variable terms correctly is essential.
Step 2
Why this answer is correct
The correct answer is A. (x<3). From (5x-4<3x+2), we get (2x<6), so (x<3). Combining variable terms correctly is essential.
Step 3
Exam Tip
(5x-4<3x+2) से (2x<6) मिलता है इसलिए (x<3) है। चर पदों को ठीक से मिलाना जरूरी है।
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असमानता \(4x+3\ge 2x+11\) का हल चुनिए।
Choose the solution of \(4x+3\ge 2x+11\).
#linear-inequalities
#variables-both-sides
#class-11
#easy
A \(x\ge 4\)
B \(x\le 4\)
C \(x\ge 7\)
D \(x\le 7\)
Explanation opens after your attempt
Correct Answer
A. \(x\ge 4\)
Step 1
Concept
\(4x+3\ge 2x+11\) gives \(2x\ge 8\), hence \(x\ge 4\). Simplify fully before choosing the answer.
Step 2
Why this answer is correct
The correct answer is A. \(x\ge 4\). \(4x+3\ge 2x+11\) gives \(2x\ge 8\), hence \(x\ge 4\). Simplify fully before choosing the answer.
Step 3
Exam Tip
\(4x+3\ge 2x+11\) से \(2x\ge 8\) और इसलिए \(x\ge 4\) मिलता है। सरल बनाने के बाद ही उत्तर चुनें।
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असमानता (3x-2>x+6) का सही हल क्या है?
What is the correct solution of (3x-2>x+6)?
#linear-inequalities
#variables-both-sides
#class-11
#easy
A (x>4)
B (x<4)
C (x>2)
D (x<2)
Explanation opens after your attempt
Step 1
Concept
From (3x-2>x+6), we get (2x>8), so (x>4). Subtracting like terms does not change the inequality sign.
Step 2
Why this answer is correct
The correct answer is A. (x>4). From (3x-2>x+6), we get (2x>8), so (x>4). Subtracting like terms does not change the inequality sign.
Step 3
Exam Tip
(3x-2>x+6) से (2x>8) मिलता है इसलिए (x>4) है। समान पद घटाने से चिन्ह नहीं बदलता।
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असमानता \(2x+5\le x+9\) का हल ज्ञात कीजिए।
Find the solution of \(2x+5\le x+9\).
#linear-inequalities
#variables-both-sides
#class-11
#easy
A \(x\le 4\)
B \(x\ge 4\)
C \(x\le 14\)
D \(x\ge 14\)
Explanation opens after your attempt
Correct Answer
A. \(x\le 4\)
Step 1
Concept
Subtracting (x) and (5) from both sides gives \(x\le 4\). Keep variable terms on one side and constants on the other.
Step 2
Why this answer is correct
The correct answer is A. \(x\le 4\). Subtracting (x) and (5) from both sides gives \(x\le 4\). Keep variable terms on one side and constants on the other.
Step 3
Exam Tip
दोनों पक्षों से (x) और (5) घटाने पर \(x\le 4\) मिलता है। चर पदों को एक ओर और संख्याओं को दूसरी ओर रखें।
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असमानता \(7-3x\ge 1\) का हल क्या है?
What is the solution of \(7-3x\ge 1\)?
#linear-inequalities
#sign-change
#class-11
#easy
A \(x\le 2\)
B \(x\ge 2\)
C \(x\le -2\)
D \(x\ge -2\)
Explanation opens after your attempt
Correct Answer
A. \(x\le 2\)
Step 1
Concept
\(7-3x\ge 1\) gives \(-3x\ge -6\), then \(x\le 2\). The inequality sign must reverse with a negative coefficient.
Step 2
Why this answer is correct
The correct answer is A. \(x\le 2\). \(7-3x\ge 1\) gives \(-3x\ge -6\), then \(x\le 2\). The inequality sign must reverse with a negative coefficient.
Step 3
Exam Tip
\(7-3x\ge 1\) से \(-3x\ge -6\) और फिर \(x\le 2\) मिलता है। ऋणात्मक गुणांक पर चिन्ह उलटना जरूरी है।
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असमानता (6-2x>0) का हल चुनिए।
Choose the solution of (6-2x>0).
#linear-inequalities
#sign-change
#class-11
#easy
A (x<3)
B (x>3)
C (x<-3)
D (x> -3)
Explanation opens after your attempt
Step 1
Concept
From (6-2x>0), we get (-2x>-6), and dividing by (-2) gives (x<3). Reverse the sign when dividing by a negative number.
Step 2
Why this answer is correct
The correct answer is A. (x<3). From (6-2x>0), we get (-2x>-6), and dividing by (-2) gives (x<3). Reverse the sign when dividing by a negative number.
Step 3
Exam Tip
(6-2x>0) से (-2x>-6) मिलता है और (-2) से भाग देने पर (x<3) मिलता है। ऋणात्मक से भाग देते समय चिन्ह पलटता है।
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असमानता \(4x-7\le 9\) का हल क्या है?
What is the solution of \(4x-7\le 9\)?
#linear-inequalities
#two-step
#class-11
#easy
A \(x\le 4\)
B \(x\ge 4\)
C \(x\le 16\)
D \(x\ge 16\)
Explanation opens after your attempt
Correct Answer
A. \(x\le 4\)
Step 1
Concept
Adding (7) gives \(4x\le 16\), and dividing by (4) gives \(x\le 4\). Dividing by positive (4) keeps the sign unchanged.
Step 2
Why this answer is correct
The correct answer is A. \(x\le 4\). Adding (7) gives \(4x\le 16\), and dividing by (4) gives \(x\le 4\). Dividing by positive (4) keeps the sign unchanged.
Step 3
Exam Tip
(7) जोड़ने पर \(4x\le 16\) और (4) से भाग देने पर \(x\le 4\) मिलता है। धनात्मक (4) से भाग देने पर चिन्ह नहीं बदलता।
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असमानता (5x+1>16) को हल कीजिए।
Solve the inequality (5x+1>16).
#linear-inequalities
#two-step
#class-11
#easy
A (x>3)
B (x<3)
C (x>17)
D (x<17)
Explanation opens after your attempt
Step 1
Concept
First subtract (1) to get (5x>15), then divide by (5) to get (x>3). Removing the constant term first makes solving easier.
Step 2
Why this answer is correct
The correct answer is A. (x>3). First subtract (1) to get (5x>15), then divide by (5) to get (x>3). Removing the constant term first makes solving easier.
Step 3
Exam Tip
पहले (1) घटाने पर (5x>15) और फिर (5) से भाग देने पर (x>3) मिलता है। पहले स्थिर पद हटाना आसान रहता है।
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असमानता \(-2x\le 8\) का सही हल क्या है?
What is the correct solution of \(-2x\le 8\)?
#linear-inequalities
#sign-change
#class-11
#easy
A \(x\ge -4\)
B \(x\le -4\)
C \(x\ge 4\)
D \(x\le 4\)
Explanation opens after your attempt
Correct Answer
A. \(x\ge -4\)
Step 1
Concept
Dividing \(-2x\le 8\) by (-2) reverses the sign and gives \(x\ge -4\). This sign reversal is a very common exam mistake.
Step 2
Why this answer is correct
The correct answer is A. \(x\ge -4\). Dividing \(-2x\le 8\) by (-2) reverses the sign and gives \(x\ge -4\). This sign reversal is a very common exam mistake.
Step 3
Exam Tip
\(-2x\le 8\) में (-2) से भाग देने पर चिन्ह उलटकर \(x\ge -4\) मिलता है। यह आसान प्रश्नों में सबसे सामान्य गलती होती है।
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असमानता \(3x\ge 18\) का हल ज्ञात कीजिए।
Find the solution of the inequality \(3x\ge 18\).
#linear-inequalities
#algebraic-solution
#class-11
#easy
A \(x\ge 6\)
B \(x\le 6\)
C \(x\ge 21\)
D \(x\le 21\)
Explanation opens after your attempt
Correct Answer
A. \(x\ge 6\)
Step 1
Concept
Dividing \(3x\ge 18\) by (3) gives \(x\ge 6\). The sign stays the same when dividing by a positive coefficient.
Step 2
Why this answer is correct
The correct answer is A. \(x\ge 6\). Dividing \(3x\ge 18\) by (3) gives \(x\ge 6\). The sign stays the same when dividing by a positive coefficient.
Step 3
Exam Tip
\(3x\ge 18\) में (3) से भाग देने पर \(x\ge 6\) मिलता है। धनात्मक गुणांक हटाते समय चिन्ह वैसा ही रहता है।
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असमानता \(x-5\le 2\) का हल चुनिए।
Choose the solution of the inequality \(x-5\le 2\).
#linear-inequalities
#algebraic-solution
#class-11
#easy
A \(x\le 7\)
B \(x\ge 7\)
C \(x\le -3\)
D \(x\ge -3\)
Explanation opens after your attempt
Correct Answer
A. \(x\le 7\)
Step 1
Concept
Adding (5) to both sides of \(x-5\le 2\) gives \(x\le 7\). Addition keeps the inequality sign unchanged.
Step 2
Why this answer is correct
The correct answer is A. \(x\le 7\). Adding (5) to both sides of \(x-5\le 2\) gives \(x\le 7\). Addition keeps the inequality sign unchanged.
Step 3
Exam Tip
\(x-5\le 2\) में दोनों पक्षों में (5) जोड़ने पर \(x\le 7\) मिलता है। जोड़ने पर असमानता का चिन्ह वही रहता है।
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असमानता (x+3>7) का हल क्या है?
What is the solution of the inequality (x+3>7)?
#linear-inequalities
#algebraic-solution
#class-11
#easy
A (x>4)
B (x<4)
C (x>10)
D (x<10)
Explanation opens after your attempt
Step 1
Concept
Subtracting (3) from both sides of (x+3>7) gives (x>4). In exams remember that subtracting the same number does not change the sign.
Step 2
Why this answer is correct
The correct answer is A. (x>4). Subtracting (3) from both sides of (x+3>7) gives (x>4). In exams remember that subtracting the same number does not change the sign.
Step 3
Exam Tip
(x+3>7) में दोनों पक्षों से (3) घटाने पर (x>4) मिलता है। परीक्षा में समान संख्या घटाने से चिन्ह नहीं बदलता।
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संयुक्त असमानता \(-2<\frac{5-x}{3}\leq 4\) का हल कौन सा है?
Which is the solution of the compound inequality \(-2<\frac{5-x}{3}\leq 4\)?
#linear inequalities
#introduction
#class 11
A \(-7\leq x<11\)
B \(-7<x\leq 11\)
C \(-11<x\leq 7\)
D \(7\leq x<11\)
Explanation opens after your attempt
Correct Answer
A. \(-7\leq x<11\)
Step 1
Concept
After multiplying by positive (3), we get \(-6<5-x\leq 12\), then the direction changes because of the negative part. The correct solution is \(-7\leq x<11\).
Step 2
Why this answer is correct
The correct answer is A. \(-7\leq x<11\). After multiplying by positive (3), we get \(-6<5-x\leq 12\), then the direction changes because of the negative part. The correct solution is \(-7\leq x<11\).
Step 3
Exam Tip
धनात्मक (3) से गुणा करने के बाद \(-6<5-x\leq 12\) मिलता है, फिर ऋणात्मक भाग के कारण दिशा बदलती है। सही हल \(-7\leq x<11\) है।
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एक कोचिंग योजना में प्रवेश शुल्क (150) रुपये और मासिक शुल्क (80m) रुपये है। यदि कुल खर्च (550) रुपये से अधिक नहीं होना चाहिए, तो (m) के लिए सही हल क्या है?
A coaching plan has an admission fee of (150) rupees and a monthly fee of (80m) rupees. If the total cost should not exceed (550) rupees, what is the correct solution for (m)?
#linear inequalities
#introduction
#class 11
A \(m\leq 5\)
B \(m\geq 5\)
C (m<5)
D (m>5)
Explanation opens after your attempt
Correct Answer
A. \(m\leq 5\)
Step 1
Concept
The cost inequality is \(150+80m\leq 550\), which gives \(m\leq 5\). Remember that not exceed means \(\leq\).
Step 2
Why this answer is correct
The correct answer is A. \(m\leq 5\). The cost inequality is \(150+80m\leq 550\), which gives \(m\leq 5\). Remember that not exceed means \(\leq\).
Step 3
Exam Tip
खर्च की असमानता \(150+80m\leq 550\) होगी, जिससे \(m\leq 5\) मिलता है। अधिक नहीं का अर्थ \(\leq\) याद रखें।
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कौन सा विकल्प \(x\in\mathbb{R}\) और (x<0) को दर्शाता है?
Which option represents \(x\in\mathbb{R}\) and (x<0)?
#linear inequalities
#introduction
#class 11
A (\(-\infty,0\))
B (\(-\infty,0]\)
C \([0,\infty\))
D (\(0,\infty\))
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,0\))
Step 1
Concept
(x<0) includes all negative real numbers and does not include (0). Therefore (\(-\infty,0\)) is correct.
Step 2
Why this answer is correct
The correct answer is A. (\(-\infty,0\)). (x<0) includes all negative real numbers and does not include (0). Therefore (\(-\infty,0\)) is correct.
Step 3
Exam Tip
(x<0) में सभी ऋणात्मक वास्तविक संख्याएं आती हैं और (0) शामिल नहीं होता। इसलिए (\(-\infty,0\)) सही है।
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असमानता \(5\leq x+2<11\) का हल क्या है?
What is the solution of \(5\leq x+2<11\)?
#linear inequalities
#introduction
#class 11
A \(3\leq x<9\)
B \(3<x\leq 9\)
C \(7\leq x<13\)
D \(2\leq x<8\)
Explanation opens after your attempt
Correct Answer
A. \(3\leq x<9\)
Step 1
Concept
Subtracting (2) from all parts gives \(3\leq x<9\). Apply the same operation to every part of a compound inequality.
Step 2
Why this answer is correct
The correct answer is A. \(3\leq x<9\). Subtracting (2) from all parts gives \(3\leq x<9\). Apply the same operation to every part of a compound inequality.
Step 3
Exam Tip
सभी भागों से (2) घटाने पर \(3\leq x<9\) मिलता है। संयुक्त असमानता में हर भाग पर समान क्रिया करें।
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कौन सा कथन (x>9) और \(x\geq 9\) में अंतर बताता है?
Which statement explains the difference between (x>9) and \(x\geq 9\)?
#linear inequalities
#introduction
#class 11
A \(x\geq 9\) में (9) शामिल है / \(x\geq 9\) includes (9)
B (x>9) में (9) शामिल है / (x>9) includes (9)
C दोनों में (9) शामिल नहीं है / (9) is not included in both
D दोनों केवल (9) को दर्शाते हैं / Both represent only (9)
Explanation opens after your attempt
Correct Answer
A. \(x\geq 9\) में (9) शामिल है / \(x\geq 9\) includes (9)
Step 1
Concept
(>) does not include the boundary, but \(\geq\) includes it. This decides the open or closed circle.
Step 2
Why this answer is correct
The correct answer is A. \(x\geq 9\) में (9) शामिल है / \(x\geq 9\) includes (9). (>) does not include the boundary, but \(\geq\) includes it. This decides the open or closed circle.
Step 3
Exam Tip
(>) सीमा को शामिल नहीं करता लेकिन \(\geq\) सीमा को शामिल करता है। इसी से खुला या बंद वृत्त तय होता है।
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किसी संख्या में (8) जोड़ने पर परिणाम (15) से कम है। सही असमानता क्या है?
A number increased by (8) is less than (15). What is the correct inequality?
#linear inequalities
#introduction
#class 11
A (x+8<15)
B (x+8>15)
C (8x<15)
D (x-8<15)
Explanation opens after your attempt
Correct Answer
A. (x+8<15)
Step 1
Concept
Increasing a number by (8) is (x+8), and less than means (<). Identify the main operation in word problems.
Step 2
Why this answer is correct
The correct answer is A. (x+8<15). Increasing a number by (8) is (x+8), and less than means (<). Identify the main operation in word problems.
Step 3
Exam Tip
संख्या में (8) जोड़ना (x+8) है और से कम का अर्थ (<) होता है। शब्द प्रश्नों में मुख्य क्रिया पहचानें।
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असमानता \(6-\frac{x}{3}\geq 2\) का हल क्या है?
What is the solution of \(6-\frac{x}{3}\geq 2\)?
#linear inequalities
#introduction
#class 11
A \(x\leq 12\)
B \(x\geq 12\)
C (x<12)
D (x>12)
Explanation opens after your attempt
Correct Answer
A. \(x\leq 12\)
Step 1
Concept
\(-\frac{x}{3}\geq -4\), and removing the negative factor gives \(x\leq 12\). Identify when the sign must be reversed.
Step 2
Why this answer is correct
The correct answer is A. \(x\leq 12\). \(-\frac{x}{3}\geq -4\), and removing the negative factor gives \(x\leq 12\). Identify when the sign must be reversed.
Step 3
Exam Tip
\(-\frac{x}{3}\geq -4\) से ऋणात्मक गुणक हटाने पर \(x\leq 12\) मिलता है। चिन्ह बदलने की स्थिति पहचानें।
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यदि \(0<x\leq 4\), तो निम्न में से कौन सा मान हल है?
If \(0<x\leq 4\), which of the following is a solution?
#linear inequalities
#introduction
#class 11
A (x=4)
B (x=0)
C (x=5)
D (x=-1)
Explanation opens after your attempt
Step 1
Concept
(0) is not included, but (4) is included. Therefore (x=4) is correct among the given options.
Step 2
Why this answer is correct
The correct answer is A. (x=4). (0) is not included, but (4) is included. Therefore (x=4) is correct among the given options.
Step 3
Exam Tip
(0) शामिल नहीं है लेकिन (4) शामिल है। इसलिए दिए गए विकल्पों में (x=4) सही है।
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कौन सा विकल्प \({x:x\leq 8}\) का अंतराल रूप है?
Which option is the interval form of \({x:x\leq 8}\)?
#linear inequalities
#introduction
#class 11
A (\(-\infty,8]\)
B (\(-\infty,8\))
C \([8,\infty\))
D (\(8,\infty\))
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,8]\)
Step 1
Concept
In \(x\leq 8\), (8) is included and all smaller values are taken. Hence (\(-\infty,8]\) is correct.
Step 2
Why this answer is correct
The correct answer is A. (\(-\infty,8]\). In \(x\leq 8\), (8) is included and all smaller values are taken. Hence (\(-\infty,8]\) is correct.
Step 3
Exam Tip
\(x\leq 8\) में (8) शामिल है और उससे छोटे सभी मान आते हैं। इसलिए (\(-\infty,8]\) सही है।
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असमानता \(-7x\leq 28\) को हल कीजिए।
Solve the inequality \(-7x\leq 28\).
#linear inequalities
#introduction
#class 11
A \(x\geq -4\)
B \(x\leq -4\)
C (x>-4)
D (x<-4)
Explanation opens after your attempt
Correct Answer
A. \(x\geq -4\)
Step 1
Concept
Dividing by (-7) reverses the sign to \(\geq\). Therefore \(x\geq -4\) is obtained.
Step 2
Why this answer is correct
The correct answer is A. \(x\geq -4\). Dividing by (-7) reverses the sign to \(\geq\). Therefore \(x\geq -4\) is obtained.
Step 3
Exam Tip
(-7) से भाग देने पर चिन्ह उलटकर \(\geq\) हो जाता है। इसलिए \(x\geq -4\) मिलता है।
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यदि \(7x\geq -21\), तो सही हल क्या है?
If \(7x\geq -21\), what is the correct solution?
#linear inequalities
#introduction
#class 11
A \(x\geq -3\)
B \(x\leq -3\)
C (x>-3)
D (x<-3)
Explanation opens after your attempt
Correct Answer
A. \(x\geq -3\)
Step 1
Concept
Dividing by positive (7) does not change the direction of the inequality. Therefore \(x\geq -3\).
Step 2
Why this answer is correct
The correct answer is A. \(x\geq -3\). Dividing by positive (7) does not change the direction of the inequality. Therefore \(x\geq -3\).
Step 3
Exam Tip
धनात्मक (7) से भाग देने पर असमानता की दिशा नहीं बदलती। इसलिए \(x\geq -3\) है।
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किस असमानता का हल \(x\geq -1\) है?
Which inequality has the solution \(x\geq -1\)?
#linear inequalities
#introduction
#class 11
A \(x+1\geq 0\)
B \(x-1\geq 0\)
C \(x+1\leq 0\)
D \(x-1\leq 0\)
Explanation opens after your attempt
Correct Answer
A. \(x+1\geq 0\)
Step 1
Concept
\(x+1\geq 0\) gives \(x\geq -1\). Solving and matching the options is a useful method.
Step 2
Why this answer is correct
The correct answer is A. \(x+1\geq 0\). \(x+1\geq 0\) gives \(x\geq -1\). Solving and matching the options is a useful method.
Step 3
Exam Tip
\(x+1\geq 0\) से \(x\geq -1\) मिलता है। विकल्पों को हल करके मिलान करना उपयोगी तरीका है।
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असमानता \(3x+7\leq x+19\) में सीमा मान क्या है?
What is the boundary value in the inequality \(3x+7\leq x+19\)?
#linear inequalities
#introduction
#class 11
A (6)
B (7)
C (8)
D (5)
Explanation opens after your attempt
Step 1
Concept
The boundary value is found by using equality: (3x+7=x+19), so (x=6). The boundary value decides the final interval.
Step 2
Why this answer is correct
The correct answer is A. (6). The boundary value is found by using equality: (3x+7=x+19), so (x=6). The boundary value decides the final interval.
Step 3
Exam Tip
सीमा मान बराबरी लगाकर मिलता है: (3x+7=x+19), इसलिए (x=6)। सीमा मान से अंतिम अंतराल तय होता है।
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यदि (x>0), तो (-2x) के बारे में क्या सही है?
If (x>0), what is true about (-2x)?
#linear inequalities
#introduction
#class 11
A (-2x<0)
B (-2x>0)
C (-2x=0)
D \(-2x\geq 0\)
Explanation opens after your attempt
Correct Answer
A. (-2x<0)
Step 1
Concept
Multiplying positive (x) by negative (-2) gives a negative result. Therefore (-2x<0) is correct.
Step 2
Why this answer is correct
The correct answer is A. (-2x<0). Multiplying positive (x) by negative (-2) gives a negative result. Therefore (-2x<0) is correct.
Step 3
Exam Tip
धनात्मक (x) को ऋणात्मक (-2) से गुणा करने पर परिणाम ऋणात्मक होता है। इसलिए (-2x<0) सही है।
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असमानता (5x+1>2x+16) का हल चुनिए।
Choose the solution of (5x+1>2x+16).
#linear inequalities
#introduction
#class 11
A (x>5)
B (x<5)
C \(x\geq 5\)
D \(x\leq 5\)
Explanation opens after your attempt
Step 1
Concept
From (3x>15), we get (x>5). Since equality is not present, (5) will not be included.
Step 2
Why this answer is correct
The correct answer is A. (x>5). From (3x>15), we get (x>5). Since equality is not present, (5) will not be included.
Step 3
Exam Tip
(3x>15) से (x>5) मिलता है। बराबरी नहीं है इसलिए (5) शामिल नहीं होगा।
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कौन सा कथन (x< -2) के बारे में सही है?
Which statement about (x<-2) is correct?
#linear inequalities
#introduction
#class 11
A (-2) हल में शामिल नहीं है / (-2) is not included in the solution
B (-2) हल में शामिल है / (-2) is included in the solution
C केवल (x=-2) हल है / Only (x=-2) is the solution
D केवल (x>-2) हल है / Only (x>-2) is the solution
Explanation opens after your attempt
Correct Answer
A. (-2) हल में शामिल नहीं है / (-2) is not included in the solution
Step 1
Concept
The strict inequality (<) does not include the boundary value. On the number line, an open circle is drawn at (-2).
Step 2
Why this answer is correct
The correct answer is A. (-2) हल में शामिल नहीं है / (-2) is not included in the solution. The strict inequality (<) does not include the boundary value. On the number line, an open circle is drawn at (-2).
Step 3
Exam Tip
कठोर असमानता (<) सीमा मान को शामिल नहीं करती। संख्या रेखा पर (-2) पर खुला वृत्त बनेगा।
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यदि (x-2<5) और \(x\in\mathbb{Z}\) तथा \(x\geq 2\), तो संभावित मान कौन से हैं?
If (x-2<5), \(x\in\mathbb{Z}\), and \(x\geq 2\), which values are possible?
#linear inequalities
#introduction
#class 11
A ({2,3,4,5,6})
B ({2,3,4,5,6,7})
C ({1,2,3,4,5,6})
D ({3,4,5,6,7})
Explanation opens after your attempt
Correct Answer
A. ({2,3,4,5,6})
Step 1
Concept
(x-2<5) gives (x<7), and \(x\geq 2\). Therefore the integer values are ({2,3,4,5,6}).
Step 2
Why this answer is correct
The correct answer is A. ({2,3,4,5,6}). (x-2<5) gives (x<7), and \(x\geq 2\). Therefore the integer values are ({2,3,4,5,6}).
Step 3
Exam Tip
(x-2<5) से (x<7) और \(x\geq 2\) है। इसलिए पूर्णांक मान ({2,3,4,5,6}) होंगे।
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असमानता (14<2x+4) का हल क्या है?
What is the solution of (14<2x+4)?
#linear inequalities
#introduction
#class 11
A (x>5)
B (x<5)
C \(x\geq 5\)
D \(x\leq 5\)
Explanation opens after your attempt
Step 1
Concept
From (10<2x), we get (5<x), that is (x>5). (5<x) and (x>5) are the same.
Step 2
Why this answer is correct
The correct answer is A. (x>5). From (10<2x), we get (5<x), that is (x>5). (5<x) and (x>5) are the same.
Step 3
Exam Tip
(10<2x) से (5<x), अर्थात (x>5) मिलता है। (5<x) और (x>5) समान हैं।
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