Hard Mathematics Chapter 1: Real Numbers Class 10 Level 18

कौन-सा कथन सही है यदि (n) विषम पूर्णांक है?

Which statement is correct if (n) is an odd integer?

Explanation opens after your attempt
Correct Answer

A. \(n^2\) विषम होगा\(n^2\) will be odd

Step 1

Concept

An odd integer can be written as (2k+1).

Step 2

Why this answer is correct

Its square becomes \(4k^2+4k+1\), which is odd.

Step 3

Exam Tip

This fact helps prove that if \(p^2\) is even, then (p) is even in the \(\sqrt{2}\) proof. चरण 1: विषम पूर्णांक को (2k+1) लिखा जा सकता है। चरण 2: उसका वर्ग \(4k^2+4k+1\) बनता है, जो विषम है। चरण 3: यह तथ्य \(\sqrt{2}\) के प्रमाण में \(p^2\) सम होने से (p) सम बताने में मदद करता है।

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The correct answer is A. \(n^2\) विषम होगा / \(n^2\) will be odd.

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