Hard Mathematics Chapter 1: Real Numbers Class 10 Level 18

यदि \(\sqrt{2}\) को परिमेय मानकर \(\sqrt{2}=\frac{p}{q}\) लिखा जाए, जहाँ (p) और (q) सहअभाज्य हैं, तो विरोधाभास मुख्य रूप से किस बात से आता है?

If \(\sqrt{2}\) is assumed rational and written as \(\sqrt{2}=\frac{p}{q}\), where (p) and (q) are coprime, where does the contradiction mainly come from?

Explanation opens after your attempt
Correct Answer

A. (p) और (q) दोनों सम हो जाते हैं(p) and (q) both become even

Step 1

Concept

Assuming \(\sqrt{2}=\frac{p}{q}\) gives \(p^2=2q^2\).

Step 2

Why this answer is correct

So \(p^2\) is even, hence (p) is even, and then (q) also becomes even.

Step 3

Exam Tip

In exams, remember that coprime numbers cannot both be even. चरण 1: \(\sqrt{2}=\frac{p}{q}\) मानने पर \(p^2=2q^2\) मिलता है। चरण 2: इससे \(p^2\) सम और इसलिए (p) सम होता है। फिर (q) भी सम निकलता है। चरण 3: परीक्षा में याद रखें कि सहअभाज्य संख्याएँ दोनों सम नहीं हो सकतीं।

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The correct answer is A. (p) और (q) दोनों सम हो जाते हैं / (p) and (q) both become even.

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