Expert Mathematics Chapter 1: Real Numbers Class 10 Level 17

यदि \(\sqrt{3}\) को परिमेय मानकर प्रमाण में विरोधाभास नहीं मिल रहा, तो कौन-सी शर्त शायद छूट गई है?

If no contradiction appears while proving \(\sqrt{3}\) irrational by assuming it rational, which condition is probably missing?

Explanation opens after your attempt
Correct Answer

A. भिन्न को सरलतम रूप में लेनाTaking the fraction in lowest form

Step 1

Concept

The contradiction works only when numerator and denominator are first assumed coprime.

Step 2

Why this answer is correct

If lowest form is missing, a common factor will not be decisive.

Step 3

Exam Tip

So write the fraction in lowest form at the start. चरण 1: विरोधाभास तभी बनेगा जब अंश और हर पहले से सहअभाज्य माने गए हों। चरण 2: सरलतम रूप छूटने पर साझा गुणनखंड मिलना निर्णायक नहीं रहेगा। चरण 3: इसलिए आरंभ में ही सरलतम भिन्न लिखें।

FAQs

Mathematics Question FAQs

What is the correct answer to this Mathematics MCQ?

The correct answer is A. भिन्न को सरलतम रूप में लेना / Taking the fraction in lowest form.

Where can I practice more Mathematics questions?

Open the subject page or level quiz links on this page to practice more active Mathematics MCQs with answers and explanations.

Related Mathematics Questions

Student Class Required

Select your class first

Quiz questions, daily challenge and practice pages will open according to your selected class. Class 11/12 ke liye stream bhi select karein.