यदि \(\frac{p}{q}\) का दशमलव सांत है और भिन्न सरलतम रूप में है तो \(q^3\) के अभाज्य गुणनखंडों के बारे में क्या सही है?
If \(\frac{p}{q}\) has a terminating decimal and is in lowest form, what is correct about the prime factors of \(q^3\)?
Explanation opens after your attempt
Correct Answer
A. केवल (2) और (5) हो सकते हैंOnly (2) and (5) can occur
Concept
For a terminating decimal, the reduced denominator (q) can contain only (2) and (5). In \(q^3\), powers increase but no new prime factor appears.
Why this answer is correct
The correct answer is A. केवल (2) और (5) हो सकते हैं / Only (2) and (5) can occur. For a terminating decimal, the reduced denominator (q) can contain only (2) and (5). In \(q^3\), powers increase but no new prime factor appears.
Exam Tip
सांत दशमलव में सरलतम हर (q) में केवल (2) और (5) हो सकते हैं। \(q^3\) में घातें बढ़ेंगी लेकिन नया अभाज्य गुणनखंड नहीं आएगा।
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