यदि (p(x)=x-2-12x+c) का एक शून्यक \(6+\sqrt{19}\) है और गुणांक परिमेय हैं, तो (c) का मान क्या होगा?
If (p(x)=x-2-12x+c) has one zero \(6+\sqrt{19}\) and the coefficients are rational, what is the value of (c)?
Explanation opens after your attempt
A. (17)
Concept
The other zero will be \(6-\sqrt{19}\), and the product is (36-19=17). In exams connect the constant term with the product of zeroes.
Why this answer is correct
The correct answer is A. (17). The other zero will be \(6-\sqrt{19}\), and the product is (36-19=17). In exams connect the constant term with the product of zeroes.
Exam Tip
दूसरा शून्यक \(6-\sqrt{19}\) होगा और गुणनफल (36-19=17) है। परीक्षा में स्थिर पद को शून्यकों के गुणनफल से जोड़ें।
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