Expert Mathematics Polynomials Class 10 Level 27

यदि (p(x)=x-2-12x+c) का एक शून्यक \(6+\sqrt{19}\) है और गुणांक परिमेय हैं, तो (c) का मान क्या होगा?

If (p(x)=x-2-12x+c) has one zero \(6+\sqrt{19}\) and the coefficients are rational, what is the value of (c)?

Explanation opens after your attempt
Correct Answer

A. (17)

Step 1

Concept

The other zero will be \(6-\sqrt{19}\), and the product is (36-19=17). In exams connect the constant term with the product of zeroes.

Step 2

Why this answer is correct

The correct answer is A. (17). The other zero will be \(6-\sqrt{19}\), and the product is (36-19=17). In exams connect the constant term with the product of zeroes.

Step 3

Exam Tip

दूसरा शून्यक \(6-\sqrt{19}\) होगा और गुणनफल (36-19=17) है। परीक्षा में स्थिर पद को शून्यकों के गुणनफल से जोड़ें।

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (p(x)=x-2-12x+c) का एक शून्यक \(6+\sqrt{19}\) है और गुणांक परिमेय हैं, तो (c) का मान क्या होगा? / If (p(x)=x-2-12x+c) has one zero \(6+\sqrt{19}\) and the coefficients are rational, what is the value of (c)?

Correct Answer: A. (17). Explanation: दूसरा शून्यक \(6-\sqrt{19}\) होगा और गुणनफल (36-19=17) है। परीक्षा में स्थिर पद को शून्यकों के गुणनफल से जोड़ें। / The other zero will be \(6-\sqrt{19}\), and the product is (36-19=17). In exams connect the constant term with the product of zeroes.

Which concept should I revise for this Mathematics MCQ?

The other zero will be \(6-\sqrt{19}\), and the product is (36-19=17). In exams connect the constant term with the product of zeroes.

What exam hint can help solve this Mathematics question?

दूसरा शून्यक \(6-\sqrt{19}\) होगा और गुणनफल (36-19=17) है। परीक्षा में स्थिर पद को शून्यकों के गुणनफल से जोड़ें।

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