Medium Mathematics Chapter 1: Real Numbers Class 10 Level 16

\(\sqrt{3}\) को परिमेय मानकर \(\sqrt{3}=\frac{a}{b}\) लिखा गया है। यदि (a) और (b) सहअभाज्य हैं, तो प्रमाण में विरोधाभास कब बनेगा?

Assume \(\sqrt{3}\) is rational and \(\sqrt{3}=\frac{a}{b}\). If (a) and (b) are coprime, when will a contradiction occur in the proof?

Explanation opens after your attempt
Correct Answer

A. जब (a) और (b) दोनों (3) से विभाज्य मिलेंWhen both (a) and (b) are found divisible by (3)

Step 1

Concept

Coprime numbers have no common factor other than (1).

Step 2

Why this answer is correct

If both are divisible by (3), the common factor is (3).

Step 3

Exam Tip

This contradiction proves \(\sqrt{3}\) irrational. चरण 1: सहअभाज्य संख्याओं में (1) के अलावा साझा गुणनखंड नहीं होता। चरण 2: यदि दोनों (3) से विभाज्य मिलें, तो साझा गुणनखंड (3) होगा। चरण 3: यही विरोधाभास \(\sqrt{3}\) को अपरिमेय सिद्ध करता है।

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The correct answer is A. जब (a) और (b) दोनों (3) से विभाज्य मिलें / When both (a) and (b) are found divisible by (3).

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